Solution :
Given :
2y''' + 15y'' + 24y' + 11y= 0
Let x = independent variable
is a differential equation.
If 
It is non homogeneous then,
The general solution = complementary solution + particular integral
If Q(x) = 0
It is called the homogeneous then the general solution = complementary solution.
2y''' + 15y'' + 24y' + 11y= 0
Auxiliary equation,
-1 | 2 15 24 11
<u> | 0 -2 - 13 -11 </u>
2 13 11 0
∴ 
The roots are
So, 
Then the general solution is :
Answer:
I hope I know but I need help my self
Call the integers 'N' and N+1.. Their sum is 2N+1. Twice their sum is 4N+2. . . Two more than that is 4N+4 and the question says that their product is equal to that. . So write N (N+1) = 4N +4, and then solve that equation to find N. I can tell you right now, by looking at it, that N is 4. You should solve the equation.
An = a1 * r^(n-1)
a1 = first term = -5
r = common ratio = -4
so ur formula is : an = -5 * -4^(n-1) <==
To move the function c units up, add c to the whole funcion
you adde -9 so you moved up -9 units or down
see each choice
A. xint is where y=0, the xint for this equaion is 9, false
B. false, slopes were not affected
C. false, they clearly changed
D. yint is where x=0, the yint is -9, true
answer is D
