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3 years ago

9

Help I’m almost out of time

1 answer:

VladimirAG [237]3 years ago

6 0

Answer: First option.

Step-by-step explanation:

You can idenfity in the figure that $\angle FCE$ is formed by two secants that intersect outside of the given circle.

It is important to remember that, by definition:

$Angle\ formed\ by\ two\ Secants=\frac{1}{2}( Difference\ of\ intercepted\ Arcs)$

Knowing this, you can set up the following equation:

$m\angle FCE=\frac{1}{2}(BD-FE)$

Therefore, you must substitute values into the equation and then evaluate, in order to find the measure of the angle $\angle FCE$ .

This is:

$m\angle FCE=\frac{1}{2}(112\°-38\°)\\\\m\angle FCE=37\°$

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Who can help me d e f thanks

12345 [234]

d)

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

e)

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

f)

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

2 years ago

PLEASE HELP! WILL GIVE BRAINLIEST!

Tomtit [17]

it would be 7.2cm

because

45÷12=3.75

so thats the scale you use

and 27÷3.75 equals 7.2

4 0

3 years ago

Can anyone help ......

Eduardwww [97]

The answer is <FGI and <HGD

5 0

3 years ago

If we divide x^3 + 3x by x, the result will be?

postnew [5]

Answer:

x^2 +3

Step-by-step explanation:

(x(x^2 +3))/x

6 0

3 years ago

Ashlynn played six rounds of golf. Her scores were 72.79,74,76,76, and 75. She really wants to have an mean of 75 after her next

Zolol [24]

Well, suppose she gets x points in 7th round. Then she wants mean to be 75, meaning

(72+79+74+76+76+75+x)/7=75

Can you find x from here?

4 0

3 years ago