The first portion is 2 and his speed during the cool down portion also 2 so I think it should be 2+2 which is 4
Answer:
2
Step-by-step explanation:
Given the data : 29, 2, 28, 30, 26, 31
Outlier ;
Lower :Q1 - (1.5 * IQR)
Upper : Q3 + (1.5 * IQR)
Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range
Using calculator :
Q1 = 26
Q3 = 30
IQR = (Q3 - Q1) = 30 - 26 = 4
Lower : 26 - (1.5 * 4) = 20
Upper : 30 + (1.5 * 4) = 36
Hence, the number in the given data which falls outside the range is 2
Answer:
a
Step-by-step explanation:
they have to win over the same customers
70 x P = 63
P=63/70 = 0.9
Since P is 1-the discount
1-discount= 0.9
discount is 0.1, or 10 %
Answer:
let p(x)=180
LCM=720
HCF=36
WE HAVE TO FIND q(x)=?
as we know that
p(x)×q(x)=LCM×HCF
NOW WE HAVE TO FIND q(x)
q(x)=LCM×HCF/p(x)
q(x)=720×36/180
q(x)=25920/180
q(x)=144
i hope this will help you