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3 years ago

9

HELP PLEASE! Which situation is a true statement about payment options?

1 answer:

Ipatiy [6.2K]3 years ago

8 0

Answer:

Keeping track of your debit card transactions

Step-by-step explanation:

I hope this helps

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Jacob wants to use an elevator to carry identical packages having the same weight. Each package weighs 3 pounds and Jacob weighs

omeli [17]

(300-99) /3 - the remainder =n

6 0

3 years ago

Read 2 more answers

A number, half of that number, and one fifth of that number are added. The result is 51. What is the original number?

Lera25 [3.4K]

Let the original number be ‘x’
Then half of that number= 1/2x or simply x/2
Similarly one fifth of that number = x/5
According to the question
x+x/2+x/5=51
Taking LCM
10x/10+2x/10+5x/10=51
Multiplying 10 throughout
10x+2x+5x=510
17x=510
x=510/17
Therefore x=30

7 0

3 years ago

In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays.Find the probability that he did not hit a bounda

Margarita [4]

Answer:

The probability of NOT hitting a boundary is (4/5).

Step-by-step explanation:

Let E: Be the event of hitting a boundary

now, Probability of any event E = $\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}$

Here, number of favorable outcomes = 6

So, P(E) = $\frac{6}{30} = \frac{1}{5}$

⇒Probability of hitting a six is 1/5

Now, P(E) + P(not E) = 1

So, P(not hitting a boundary ) = 1 - P(hitting a boundary)

= 1 - (1/5) = 4/5

Hence, the probability of NOT hitting a boundary is (4/5).

4 0

3 years ago

To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x

Fiesta28 [93]

Given function is

$f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.$

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

$kx^2-5$

so RHD= $k(-4)^2-5$

Now set both equal

$k(-4)^2-5=3(-4)+k$

$16k-5=-12+k$

$16k-k=-12+5$

$15k=-7$

$k=-\frac{7}{15}$

k=-0.47

<u>Hence final answer is -0.47.</u>

7 0

3 years ago

4(x-2)-5x>-1 grater or equal I’m bad at this

Lunna [17]

X<-7 so the answer would be greater*

4 0

3 years ago