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DochEvi [55]
3 years ago
6

Whats 99 divided by 11 times 2

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0
The correct answer is 18
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Give that j ll k, what is the measure of the missing angle?<br><br>A)30°<br>B)40°<br>C)60°<br>D)120°
kondaur [170]
Missing angle is 60 degrees
8 0
2 years ago
Find the value of $x$ for the right triangle. A right triangle with base labeled x and hypotenuse labeled 12 units. Angle betwee
slamgirl [31]

Answer:

6 feets

Step-by-step explanation:

The triangle described in the question has been sketched in the picture attached below :

From the triangle, we could solve for X, which is the base of the triangle using trigonometry :

Sinθ = opposite / hypotenus

Sin 30° = x / 12

0.5 = x / 12

x = 12 * 0.5

x = 6 feets

Hence base, x = 6 feets

8 0
3 years ago
What is the average of 4 1/2, 3 1/3, 2 , 2 1/6
Zinaida [17]

Answer:

3

Step-by-step explanation:

To find the average add all these numbers together, then divide by how many numbers you have.

4\frac{1}{2} +3\frac{1}{3} +2+2\frac{1}{6} =12

\frac{12}{4} =3

Answer: 3

4 0
3 years ago
HELP ASAPPP!
Blababa [14]

Answer: 1.50x+3.50\leq 30

Step-by-step explanation:

x represents how many miles after the pick-up. we add on 3.50 because that is the intial pick-up price. then the cost has to be under 30 because she only has 30 dollars

4 0
2 years ago
Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the
maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

y=ax^2+bx+c

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

x_v=-\frac{b}{2a}

In this problem, we have:

y=-x^2-6x-13

Then:

a = -1

b = -6

We write now:

x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

-x^2-6x-13=0

To solve this, we can use the quadratic formula:

x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}

And solve:

x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0:

y=-0^2-6\cdot0-13=-13

The y-intercept is at (0, -13)

Part 5:

Now we need to find two points in the parabola. Let-s evaluate the function when x = 1 and x = -1:

x=1\Rightarrow y=-1^2-6\cdot1-13=-1-6-13=-20x=-1\Rightarrow y=-(-1)^2-6\cdot(-1)-13=-1+6-13=-8

The two points are:

(1, -20)

(-1, -8)

Part 6:

Now, we can use 3 points to find the graph of the parabola.

We can locate (1, -20) and (-1, -8)

The third could be the vertex. We need to find the y-coordinate of the vertex. We know that the x-coordinate of the vertex is x = -3

Then, y-coordinate of the vertex is:

y=-(-3)^2-6(-3)-13=-9+18-13=-4

The third point we can use is (-3, -4)

Now we can locate them in the cartesian plane:

And that's enough to get the full graph:

8 0
10 months ago
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