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Aleksandr-060686 [28]

3 years ago

10

One bag contains 7 red chips and 4 yellow chips. Another bag contains 2 red chips and 8 yellow chips. A chip is drawn from each

bag. What is the probability that both chips are yellow?

1 answer:

IgorC [24]3 years ago

4 0

Answer:

We have 11 chips in the first bag and 4 are yellow......so the probability of drawing a yellow

Step-by-step explanation:

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CAN SOMEONE HELP ME WITH B AND C PLEASE? I'LL MARK AS BARAINLIEST

Finger [1]

Since the radius of the semi circle is 10 cm then the diameter is 20 cm, when folded, its circumference is now 20, given the circumference find the radius of the cone. i guess

Volume = 1/3 πr2 (l2﹣r2)1/2

circumference = 20 cm = πD

D=6.363636364

Radius = 6.363636364/2 = 3.181818182

l = 10

vol = 100.51cm3

curved s.a = πrl

=99.96cm2

6 0

3 years ago

Consider the conditional statement of N is the midpoint of CD then CD =2CN what is the hypothesis

iogann1982 [59]

Answer:

Step-by-step explanation:

If N is the midpoint of CD, it means that N bisects the line CD. Hence;

CN + ND = CD .... 1 and;

CN = ND .... 2

Substitute equation 2 into 1;

CN + CN = CD

2CN = CD

Rearrange;

CD = 2CN (proved)

The hypothesis is the midpoint hypothesis and the hypothesis is TRUE

5 0

3 years ago

Abby, Deborah, Mei-Ling, Sam, and Roberto work in a firm's public relations office. Their employer must choose two of them to at

sattari [20]

Answer:

a) Ω = { {Abby, Deborath}, {Abby, Mei-Ling}, {Abby, Sam}, {Abby,Roberto}, {Deborah, Mei-Ling}, {Deborah, Sam}, {Deborah, Roberto}, {Mei-Ling, Sam}, {Mei-Ling, Roberto}, {Sam, Roberto} }

b) 0.1

c) 0.4

d) 0.3

Step-by-step explanation:

a) The sample space must contain every possible combination of two names. Since we dont care about the <em>order</em> of the chosen names, we can describe every element of the sample space as a <em>subset</em> of 2 elements of the set {Abby, Deborah, Mei-Ling, Sam, Roberto}. That subset will represent the names of the chosen persons. With this in mind, we conclude that the sample space is

Ω = { {Abby, Deborath}, {Abby, Mei-Ling}, {Abby, Sam}, {Abby,Roberto}, {Deborah, Mei-Ling}, {Deborah, Sam}, {Deborah, Roberto}, {Mei-Ling, Sam}, {Mei-Ling, Roberto}, {Sam, Roberto} }

b) The cardinality of the sample space Ω is 10. Since all choices are <em>equally likely</em>, any choice will have probability $\frac{1}{10} = 0.1$ , because the 10 of them combined must add up 1.

c) We need to find all possible choices that includes Mei-Ling, those will be our <em>favourable cases. </em>The amount of favourable cases must be divided to the total amount of cases (the cardinality of Ω) in order to obtain the probability of Mei-Ling being chosen. Mei-Ling is included on 4 choices (one for each of her partners), this means that she has a probability of $\frac{4}{10} = 0.4$ to being chosen.

d) We have <em>3 favourable cases </em>,the choices {Abby, Deborah}, {Abby, Mei-Ling} and {Deborah, Mei-Ling}, which neither of them contain a man. By dividing that number to the total number of cases, we obtain a probability of $\frac{3}{10} = 0.3$ that neither of the two men are chosen

7 0

3 years ago

Plz help i do not understand the question.

gavmur [86]

The question is asking you to come up with a real-life example of something that can be represented as 15+ c= 17.50. If I were you I would do sales tax. You bought an item with a 15 dollar price tag, but when you go to check out 2.50 are added in tax to equal 17.50. to solve subtract 15 from 17.50: c= 2.50. Your variable (c) represents the sales tax. Hope that helps! :)

6 0

4 years ago

Don’t know how to solve it. Answers?

erastovalidia [21]

The range is the difference between the highest amount and lowest amount:

Highest = 22

Lowest= 6

Range = 22 - 6 = $16

5 0

4 years ago