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vova2212 [387]
3 years ago
8

Please help out with this geometry homework I was assigned. And what formula do I use?

Mathematics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

V_{cone}   \approx 1,178.97 \:  {in}^{3}

Step-by-step explanation:

Diameter of cone = 16 in

Radius of cone r = 16/2 = 8 in

Height of cone h = 17.6 in

V_{cone}  =  \frac{1}{3} \pi {r}^{2}h \\  \\  V_{cone}  =  \frac{1}{3}  \times 3.14 \times  {(8)}^{2} \times 17.6 \\  \\   V_{cone}  =  \frac{1}{3}  \times 3,536.896 \\  \\  V_{cone}  =  1,178.96533 \\  \\  V_{cone}   \approx 1,178.97 \:  {in}^{3}  \\

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2 years ago
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Wittaler [7]

Answer:

<h3><u>7. Ans ;</u></h3>

\frac{41}{3}  < 14 <  \sqrt{200}

<h3><u>8</u><u>.</u><u> </u><u>Ans</u><u> </u><u>;</u></h3>

<u>0.6 <  \frac{2}{3}  <  \sqrt{ \frac{9}{16} }</u>

Step-by-step explanation:

<h3><u>7. Ans ;</u></h3>

\sqrt{200}  = 10 \sqrt{2}  = 14.1 \\ 14 = 14 \\  \frac{41}{3}  = 13.6

So ;

\frac{41}{3}  < 14 <  \sqrt{200}  \\ 13.6 < 14 < 14.1

<h3><u>8. Ans ;</u></h3>

\frac{2}{3}  = 0.66 \\  \sqrt{ \frac{9}{16} }   =   \frac{3}{4}  = 0.75 \\ 0.6 = 0.6

So ;

0.6 <  \frac{2}{3}  <  \sqrt{ \frac{9}{16} }  \\ 0.6 < 0.66 < 0.75

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Step-by-step explanation:

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