Let cos x =1√10 with x in QIV and find: cot2x
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Set up the equation as follows:
150x represents the dog's speed, 100x represents the squirrel's speed, and 200 represents the distance the squirrel has on the dog. x is the amount of minutes that elapse.
Subtract 100x from both sides.
Divide both sides by 50.
It will take the dog 4 minutes to catch up with the squirrel.
150x represents the dog's speed, 100x represents the squirrel's speed, and 200 represents the distance the squirrel has on the dog. x is the amount of minutes that elapse.
Subtract 100x from both sides.
Divide both sides by 50.
It will take the dog 4 minutes to catch up with the squirrel.