Question

Bonnie volunteers to bring bags of candy to her child's class for the Halloween party. She buys a bag containing 240, a bag containing 624, and a bag containing 336 pieces. Age needs to use all the candy to create identical treat bags. How many treat bags can bonnie make so that each one has the same number and variety of candy? How many of each type of candy will be in each bag?

Answer 1

Answer:

Number of bags that Bonnie can make so that each one has the same number of candies = 48

Number of candies from bag I in each of the treat bag = 5

Number of candies from bag II in each of the treat bag = 13

Number of candies from bag III in each of the treat bag = 7

Step-by-step explanation:

Given: One bag (I) has 240 candies, one bag (II) has 624 candies and one bag (III) has 336 candies

To find: Number of bags that Bonnie can make so that each one has the same number of candies and number of each type of candies in each bag

Solution:

$240=2^4\times 3\times 5\\624=2^4\times3\times13\\336=2^4\times3\times7$

Highest common factor (H.C.F) = $2^4\times3=48$

So,

Number of bags that bonnie can make so that each one has the same number of candies = 48

Now,

$\frac{240}{48}=5\\ \frac{240}{48}=13\\\frac{240}{48}=7$

Number of candies from bag I in each of the treat bag = 5

Number of candies from bag II in each of the treat bag = 13

Number of candies from bag III in each of the treat bag = 7