The amount of heat needed to cook the pork roast is 1700 kJ.
The amount of heat absorbed by the roast is 14% of the heat produced = 14% X ?H = 310.38 kJ/mol
One mole of propane burns to produce 3 moles of CO2 and -2217 kJ of heat.
1700kJ/ (14% X ?H) = mol of C3H8 burned
1700kJ / (310.38 kJ/mol) = 5.48 mol C3H8
Since 3 moles of CO2 are produced:
3 X 5.48 mol= 16.43 mols of CO2
convert moles to grams:
16.43 mol CO2 X 44.0g/mol ~ 722.9 g CO2 produced
Answer:
i did
Step-by-step explanation:
i already turned it in thoo
Answer:
The first
Step-by-step explanation:
The intercept is a negative so the line will be going the opposite way
Answer:
The least common denominator of the fraction is 14
1/2= 7/14
1/7= 2/14
