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Lapatulllka [165]
3 years ago
9

To prove ABC= ADC, To prove which triangle postulate could you use?

Mathematics
2 answers:
Kay [80]3 years ago
6 0

Answer:

ASA

Step-by-step explanation:

..................

Llana [10]3 years ago
5 0
I’m pretty sure it’s ASA
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During a recent thunderstorm, the temperature dropped 24° in 3 hours. What integer completes the equation to find the average ho
Gala2k [10]
The formula is

T=Temperature
H=Hours

T=-8(h)
6 0
3 years ago
Could someone tell me the correct answer and how to do this. Plz help meeee I'm crying because I don't know how to do this stuff
WINSTONCH [101]
Hey don't cry . I'm not good at math either but try to take a deep breath.
8 0
3 years ago
What is the solution to the system of equations?
alukav5142 [94]

Answer:

  (x, y) = (-4, 15)

Step-by-step explanation:

The two equations have the same coefficient for y, so you can eliminate y by subtracting one equation from the other. Here the x coefficient is largest for the first equation, so it will work best to subtract the second equation.

  (3x +y) -(2x +y) = (3) -(7)

  x = -4 . . . . . . . . simplify

Now, we can find y by substituting this value for x.

  2(-4) +y = 7

  y = 7 +8 = 15 . . . . . add 8 to both sides of the equation

The solution is (x, y) = (-4, 15).

6 0
3 years ago
A researcher conducted a paired sample t-test to determine if advertisements were viewed more in the morning (before noon) or in
Natalija [7]

Answer:

b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).

Step-by-step explanation:

The critical value for one tailed test is t ∝(7) > 1.895

A one tailed test is performed to test the claim that advertisements were viewed more in the morning (before noon) or in the evening (after 5pm)

The null and alternative hypotheses are

H0: μm = μe   vs     Ha μm > μe

where μm is the mean of the morning and μe is the mean of evening.

The calculated value of t = -1.152587077  which is less than the critical region hence the null hypothesis cannot be rejected .

P(T<=t) one-tail 0.143458126 > 0.05

If two tailed test is performed the critical region is t Critical two-tail 2.364624252

and the calculated t value is  -1.152587077  which again does not lie in the critical region .

Hence μm =  μe or    μm ≤ μe

P(T<=t) two-tail 0.286916252  > 0.025

Therefore

b. No, there was no difference between Morning (M= 32), and Evening (M=40.625), (t [7] = 1.15, p > .05).

Option b gives the best answer.

6 0
3 years ago
Can you solve or nahh
Zielflug [23.3K]
1.06, 1.16, 1.6, 1.62, 1.66
6 0
3 years ago
Read 2 more answers
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