Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or 
ft
= 
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
= 
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k()
k = 18
Work done (W) to stretch the spring by ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9()²
= 7.56 lb-ft
Answer:
yes you can.
Step-by-step explanation:
to answer the question asked you can solve a proportion when given two triangles, but in this one I feel somethings missing like its possibly a multiple choice.
I tried every way I could think of and got this 6.5 for the bottom A-B
and for x about 4.153311-
Use proportions here - 8/5.2 = 96/width of actual car. using cross multiplication, 5.2*96 = 8x. this gives you 499.2 = 8x. divide both sides by eight to get x=62.4. the width of the actual car is 62.4 inches.
Answer:
r = 2.39 and C=2πr=2·π·2.39≈14.99997
Step-by-step explanation:
Using the formula
C=2πr
Solving for r=C 2π=15
2·π≈2.38732
and then u round up the 7 told the 8 to go up.
2.39
34! Find the area of each of the six sides and then add them up:)
