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Mandarinka [93]
3 years ago
9

The hanger image below represents a balanced equation.

Mathematics
2 answers:
nikdorinn [45]3 years ago
6 0

Answer:

Where is the picture?

Step-by-step explanation:

goldfiish [28.3K]3 years ago
3 0
I think you forgot to put the image in the question
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Can someone please help me
Rzqust [24]

Answer:

the graph of the function is non-linear

the table can be represented by the equation y=4x+4

Step-by-step explanation:

non linear because 1+7=8 and then 10+2 = 12 so they have different numbers to add each time

represented by the equation because the x numbers (1,2,3,4,) all multiplied by 4 and added by 4 gives you y

any more help just ask :)

3 0
3 years ago
A customer at Lost Pastores placed an order for 3 burritos which was priced at x amount of dollars each. He also ordered a plate
timofeeve [1]

Answer:

3x +12.95 = 32.46

Step-by-step explanation:

3 burritos plus x + 12.95 = $32.46

3 0
3 years ago
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I need help with rhombus,rectangles and squares<br>​
AnnZ [28]

Answer:

a= 11, b= 12

Opposite angles of parallelogram are equal.

m<D = m<B

9b-2=106°

9b= 108°

b= 12°

Sum of the adjacent angles of a parallelogram = 180°

m<B+m<C = 180°

106°+7a-3=180°

7a = 180°-106°+3

7a=77°

a= 11°

4 0
3 years ago
Help , please and thanks
ira [324]

Answer:

891,962,172,409

try that

Step-by-step explanation:

5 0
4 years ago
What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1
Ratling [72]

Answer:

\sqrt3

Step-by-step explanation:

To find:

The value of tan60^\circ = ?

Solution:

Kindly consider the equilateral \triangle ABC as attached in the answer area.

Let the side of triangle = a units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = \frac{a}{2}

Using Pythagorean Theorem in \triangle ABD:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}

Side AD = \frac{\sqrt3}{2}a

Using Trigonometric ratio:

tan\theta = \dfrac{Perpendicular}{Base}

tanB = \dfrac{AD}{BD}

Putting the values of AD and BD:

tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}

5 0
3 years ago
Read 2 more answers
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