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otez555 [7]
3 years ago
15

How many solutions does this equation have? 3y = –4 + 2y

Mathematics
2 answers:
Flura [38]3 years ago
8 0

Answer:

y=-4, one solution.

Step-by-step explanation:

3y=-4+2y

3y-2y=-4

y=-4

Akimi4 [234]3 years ago
4 0

Answer:

4

Step-by-step explanation:

3y - 4 + 2y

0 = 3y - 4 + 2y

4 + 0 = 3y - 2y

4 = y

y = 4

is this what you want ?

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LUCKY_DIMON [66]
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7 0
3 years ago
A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic
Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are​ defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are​ defective?

Solution:

Let the random variable <em>X</em> represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.

A random sample of <em>n</em> = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.

The probability mass function of <em>X</em> is:

P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...

Compute the probability that none of the LED light bulbs are​ defective as follows:

P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}

                =1\times 1\times 0.737424\\=0.737424\\\approx 0.7374

Thus, the probability that none of the LED light bulbs are​ defective is 0.7374.

6 0
3 years ago
What is 98,464 rounded to the nearest ten thousands ?
sleet_krkn [62]
100,000
because the 8 makes the 9 round up into a 10
6 0
3 years ago
Simplest form <br> 7/15 - 1/5
Lunna [17]

Answer:

4/15

Step-by-step explanation:

7/15 - 3/15 = 4/15

8 0
3 years ago
Read 2 more answers
Find the degree of the monomial.<br> 1/3x^5y
zloy xaker [14]

Answer:

6

Step-by-step explanation:

5 0
2 years ago
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