3
2
+
3
−
7
Distribute
(
6
2
−
4
−
5
)
−
1
(
3
2
−
7
+
2
)
(
6
x
2
−
4
x
−
5
)
−
1
(
3
x
2
−
7
x
+
2
)
(6x2−4x−5)−1(3x2−7x+2)
(
6
2
−
4
−
5
)
−
3
2
+
7
−
2
Answer:
The probability that none of the LED light bulbs are defective is 0.7374.
Step-by-step explanation:
The complete question is:
What is the probability that none of the LED light bulbs are defective?
Solution:
Let the random variable <em>X</em> represent the number of defective LED light bulbs.
The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.
A random sample of <em>n</em> = 10 LED light bulbs is selected.
The event of a specific LED light bulb being defective is independent of the other bulbs.
The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.
The probability mass function of <em>X</em> is:

Compute the probability that none of the LED light bulbs are defective as follows:


Thus, the probability that none of the LED light bulbs are defective is 0.7374.
100,000
because the 8 makes the 9 round up into a 10
Answer:
4/15
Step-by-step explanation:
7/15 - 3/15 = 4/15
Answer:
6
Step-by-step explanation: