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tensa zangetsu [6.8K]

2 years ago

6

PLease helppppppppp

" alt="-2x^4*(x^-4)^2" align="absmiddle" class="latex-formula">

1 answer:

Readme [11.4K]2 years ago

5 0

Answer:

No sepo ingles

Step-by-step explanation:

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Which nets match Figure g shown below <br><br> Select all that apply <br><br> Need help

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Step-by-step explanation:

i cant see figure g

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3 years ago

The braking time of a car is it discrete or continuous?

Rom4ik [11]

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Step-by-step explanation:

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3 years ago

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Use the drawing tools to form the correct answer on the grid.

Rus_ich [418]

Answer:

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Step-by-step explanation:

Draw a line exactly from 120 to the top of number 9 on the x axis labeled # of Books

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7 0

3 years ago

7x10 to the 3rd power, write a pattern to find the value of the expression

myrzilka [38]

Scientific notation is used to express very large or very small values.
Numbers in scientific notation are written in the form of
m × 10 to the power of n
For example:
500 is written as 5 x 10^2 where:
500 = 5 x 10 x 10

Now, let's consider 7 x 10^3:
Following the same procedure:
7 x 10^3 = 7 x 10 x 10 x 10 = 7000
The pattern can be written as:
7 x 10^3 = 7 x 10 x 10^2
= 70 x 10^2
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6 0

3 years ago

The augmented matrix of a system of equations has been transformed to an equivalent matrix inâ€‹ row-echelon form. Usingâ€‹ x, y

jenyasd209 [6]

Answer: The system of equations is:

x + 2y + 2 = 4

y - 3z = 9

z = - 2

The solution is: x = -22; y = 15; z = -2;

Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a <u>Row</u> <u>Echelon</u> <u>Form,</u> which satisfies the following conditions:

There is a row of all zeros at the bottom of the matrix;
The first non-zero element of any row is 1, which called leading role;
The leading row of the first row is to the right of the leading role of the previous row;

For this question, the matrix is a Row Echelon Form and is written as:

$\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]$ $\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]$

or in system form:

x + 2y + 2z = 4

y + 3z = 9

z = -2

Now, to determine the variables:

z = -2

y + 3(-2) = 9

y = 15

x + 30 - 4 = 4

x = - 22

The solution is (-22,15,-2).

4 0

3 years ago