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bija089 [108]
3 years ago
14

Austin walks 1/3 of the way to school and stopped to rest. Devyn walks 2/6 of the way to the school and stops to rest who travel

ed further
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
7 0

Answer:

Austin and Devyn.

Step-by-step explanation:

1/3 and 2/6 are equal fractions.

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You divide a number and get a remainder of 4. what 1 - digit number can the divisor of the problem?
ahrayia [7]

Answer:

<em>Any of the numbers 5,6,7,8,9 could be the divisor of the problem.</em>

Step-by-step explanation:

<u>Division</u>

If I divide a number and get a remainder of 4, then the divisor must be greater than 4. A divisor of 4, for example, would lead to a remainder of (maximum) 3.

Thus, our divisor can only be one among the numbers: 5,6,7,8,9. If the dividend is exactly 4, then the divisions

4/5, 4/6, 4/7, 4/8, and 4/9

they all produce the same remainder of 4.

Thus, any of the numbers 5,6,7,8,9 could be the divisor of the problem

6 0
3 years ago
Which function is best represented by this graph?
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Answer:

y=\frac{2}{7}x-2

Step-by-step explanation:

Slope intercept form is a way to describe a function using its slope and y-intercept and is written as y=mx+b.

m=slope

b=y-intercept

Looking at the graph we can see it goes through x=0 at y=-2 making -2 the y-intercept.

Then we must solve for slope, slope is rise/run. From the point (0,-2) the function travels to (7,0).

This gives us a rise (change in x) of 2 and a run (change in y) of 7 and 2/7 as our slope.

4 0
3 years ago
Find the quotient:<br> -35x3-10x<br> 5x
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Answer:

1. is A

and

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Step-by-step explanation:

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hammer [34]

Step-by-step explanation:

Consider the provided multiplication.

We need to use associative property of multiplication.

Associative property of multiplication:

(a\times b)\times c = a\times (b\times c)

Now use the above property and solve the provided multiplication:

(8 \times 1)\times 3 = 8 \times (1 \times 3)

8\times 3 = 8 \times 3

24 = 24

The multiplication is verified by associative property.

4 0
3 years ago
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