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Troyanec [42]
3 years ago
10

4x + 20=? it’s hard and i’m confused

Mathematics
2 answers:
seropon [69]3 years ago
6 0

Answer:

x = -5

Step-by-step explanation:

<u>This is for if you are trying to solve for x. If that is not your goal, do not heed my words.</u>

Subtract 20 from both sides.

4x + 20 = ?

becomes

4x = -20

Divide both sides by 4.

4x = -20

becomes

x = -5

And that's how you'd solve for x.

NikAS [45]3 years ago
3 0

Answer:

4(x+5) I

Step-by-step explanation:

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Answer:

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3 years ago
g (15 points) Suppose 42 out of 600 rats exposed to a potential carcinogen develop tumors. A control group of 350 rats not expos
vazorg [7]

Answer:

a) The relative risk is 1.8\overline{846153}

b) The attributable risk is 0.69 \overline{047619}

c) There is a relationship between exposure and tumor risk

Step-by-step explanation:

The number of exposed rats that develop tumors, a = 42

The number of rats exposed to the carcinogen = 600 rats

The number of exposed rats that did not develop tumors, b = 600 - 42 = 558

The number of not exposed rats in the control group = 350 rats

The number of rats that develop tumors in the control group, c = 13 tumors

The number of not exposed rats that did not develop tumors, d = 350 - 13 = 337  rats

a) The relative risk, RR = a/(a + b)/(c/(c + d))

∴ RR = (42/(42 + 558))/(13/(13 + 337)) = 49/26 = 1.8\overline{846153}

b) The attributable risk = (a - c)/a

∴ The attributable risk = (42 - 13)/42 = 0.69 \overline{047619}

c) The odds ratio = (a·b)/(c·d)

∴ The odds ratio = 42 × 558/(13 × 337) = 23439/4381 ≈ 5.35

Given that the result of attributable risk is positive, there is an indication that there is a higher probability to develop tumor when exposed to the potential carcinogen, therefore, there is a relationship between exposure and tumor risk

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3 years ago
HELP ASAP
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Answer:

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Step-by-step explanation:

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3 years ago
It takes 120 newspapers to fill 8 recycling bins. What is the unit rate in newspapers per recycling bin?
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3 years ago
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A hypothesis test is to be performed for a population proportion. For the given sample data and null hypothesis, compute the val
liberstina [14]

Answer:

The correct option is a

Step-by-step explanation:

From the question we are told that

    The sample size is n =  415

    The sample proportion is  \r p  = 0.49

Now

     The null hypothesis is  H_o  :  p = 0.3

     The alternative hypothesis is H_a  :  p \ne 0.3

The test statistics is mathematically evaluated as

      t  =  \frac{\r p -  p  }{ \frac{\sqrt{ p (1- p )} }{n} }

substituting values

      t  =  \frac{0.49 -  0.3  }{ \sqrt{ \frac{0.3 (1- 0.3 ) }{415} }}

     t  = 8.446

     

8 0
3 years ago
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