Ask question

Ask question

All categories

3 years ago

13

How does a plant cell accomplish cytokinesis

1 answer:

pychu [463]3 years ago

8 0

Answer:Cytokinesis in plant cells involves plants using spindle structures called phragmoplasts to carry vesicles of the cell wall material such as cellulose to the new cell plate. ... After the plate divides the plant cells into two daughter cells, the plasma membrane seals off and fully separates the two new cells. During cytokinesis in animal cells, a ring of actin filaments forms at the metaphase plate. The ring contracts, forming a cleavage furrow, which divides the cell in two. In plant cells, Golgi vesicles coalesce at the former metaphase plate, forming a phragmoplast.

Explanation:

You might be interested in

Where does the hydrogen that is used in Stage 2 of photosynthesis come from?

kolezko [41]

Hydrogen comes from Water that is split apart in Stage 1

8 0

2 years ago

A group of atoms such as OH is called a(n)?

marusya05 [52]

Answer:

Explanation:

They are heteroatomic atoms having two different types of atoms.

4 0

3 years ago

The key element found in compounds?

Alex Ar [27]

The most common elements present in organic compounds are carbon, hydrogen, oxygen, and nitrogen.

6 0

2 years ago

Read 2 more answers

What does each person do just before becoming infected?

Makovka662 [10]

Answer:

They became careless and transferred to every body saying i cant all of us has to die

7 0

3 years ago

An owl has good night vision because its eyes can detect a light intensity as small as 5.0 × 10-13 W/m2. What is the minimum num

Lady bird [3.3K]

Answer:

Thus, the minimum number of photons per second is 77.34

Explanation:

Light intensity, $I_{min}$ = $5\times 10^{-13} W/m^{2}$

Pupil has a diameter, d = 8.5 mm

= 8.5 x $10^{-3}$ m

Radius of the eye, r = 4.25 x $10^{-3}$ m

∴ Area of the eye, A = $\pi .r^{2}$

= $3.14\times \left ( 4.25\times 10^{-3} \right )^{2}$

= $5.6\times 10^{-5} m^{2}$

Let $P_{min}$ be the minimum number of photons.

Therefore, $P_{min}$ = $I_{min}$ x A

= $5\times 10^{-13}$ x $5.6\times 10^{-5}$

= $2.8\times 10^{-17}$ W

Thus the minimum number of photons is given by

$N_{min}=P_{min}/E$

where E = $hc/\lambda$

= $\left (6.63\times 10^{-34}\times 3\times 10^{8} \right )/548\times 10^{-9}$

= $3.62\times 10^{-19} J$

Therefore, $N_{min}$ = $\frac{2.8\times 10^{-17}}{3.62\times 10^{-19}}$

= 77.34 photons per second

Thus, the minimum number of photons per second is 77.34

4 0

3 years ago