Answer:
A) Median: 7
Mode: 8
Range: 5
B) Tyler is wrong, the greater the MAD value, the greater the variability
Step-by-step explanation:
A) Given the data set: 4,6,6,7,7,8,8,8,9
The median is 7 (the middle point in the ordered list)
The mode is 8 (the most repeated number)
The range is 5 (the difference between the highest and lowest values)
Answer:
x > -5 in the answer
Step-by-step explanation:
(5 - 3x) / 4 < 5
multiplying both sides by 4:-
5 - 3x < 20
-3x < 15
x > 15/-3
x > -5 (Note the inequality sign is flipped because we are dividing by a negative number)
ANSWER:
Segment TS is a Chord
If AR = 14 , then QS = 14 ×2 = 28
∆ATS is an Isosceles Triangle
<em><u>HOPE</u></em><em><u> </u></em><em><u>THIS</u></em><em><u> HELP</u></em><em><u> </u></em><em><u>YOU </u></em><em><u>,</u></em><em><u> FOR</u></em><em><u> ANY</u></em><em><u> QUESTION</u></em><em><u> PLEASE</u></em><em><u> ASK</u></em><em><u> </u></em><em><u>ME</u></em>
We use P = i•e^rt for exponential population growth, where P = end population, i = initial population, r = rate, and t = time
P = 2•i = 2•15 = 30, so 30 = 15 [e^(r•1)],
or 30/15 = 2 = e^(r)
ln 2 = ln (e^r)
.693 = r•(ln e), ln e = 1, so r = .693
Now that we have our doubling rate of .693, we can use that r and our t as the 12th hour is t=11, because there are 11 more hours at the end of that first hour
So our initial population is again 15, and P = i•e^rt
P = 15•e^(.693×11) = 15•e^(7.624)
P = 15•2046.94 = 30,704