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Y_Kistochka [10]

3 years ago

10

How do I solve this??

1 answer:

Liula [17]3 years ago

7 0

2(2p + m) = 3 - 5m

Distributive

4p + 2m = 3 - 5m

2m + 5m = 3 - 4p

7m = 3 - 4p

m = (3 - 4p)/ 7

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Pls help i will give you a 5 star rating

docker41 [41]

Question # 1

Given the expression

$6^2\div \:3+\left(5+3\cdot \:2\right)-2^3$

Follow the PEMDAS order of operations

$\mathrm{Calculate\:within\:parentheses}\:\left(5+3\cdot \:2\right)\::\quad 11$

$=6^2\div \:3+11-2^3$

$\mathrm{Calculate\:exponents}\:6^2\::\quad 36$

$=36\div \:3+11-2^3$

$\mathrm{Calculate\:exponents}\:2^3\::\quad 8$

$=36\div \:3+11-8$

$\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:36\div \:3\::\quad 12$

$=12+11-8$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:12+11-8\::\quad 15$

$=15$

Therefore,

$6^2\div \:3+\left(5+3\cdot \:2\right)-2^3=15$

Question # 2

Given the expression

$\frac{4+3^2-15\div 5}{\left(2^4-5\cdot \:3\right)^2}$

as

$4+3^2-\frac{15}{5}$

$=4+9-\frac{15}{5}$ ∵ $3^2=9$

$\mathrm{Add\:the\:numbers:}\:4+9=13$

$=-\frac{15}{5}+13$

and

$\left(2^4-5\cdot \:3\right)^2$

$=\left(16-5\cdot \:3\right)^2$ ∵ $2^4=16$

$\mathrm{Multiply\:the\:numbers:}\:5\cdot \:3=15$

$=\left(16-15\right)^2$

$\mathrm{Subtract\:the\:numbers:}\:16-15=1$

$=1^2$

$\mathrm{Apply\:rule}\:1^a=1$

$=1$

Thus the equation $\frac{4+3^2-15\div 5}{\left(2^4-5\cdot \:3\right)^2}$ becomes

$=\frac{-\frac{15}{5}+13}{1}$

$\mathrm{Divide\:the\:numbers:}\:\frac{15}{5}=3$

$=\frac{-3+13}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-3+13$

$\mathrm{Add/Subtract\:the\:numbers:}\:-3+13=10$

$=10$

Therefore,

$\frac{4+3^2-\frac{15}{5}}{\left(2^4-5\cdot \:3\right)^2}=10$

Question # 3

Given the expression

$ab-c^2+2b$

Putting a = 2, b = 4, and c = 1 in the expression

$=\left(2\right)\left(4\right)-\left(1\right)^2+2\left(4\right)$

Follow the PEMDAS order of operations

$\mathrm{Calculate\:exponents}\:\left(1\right)^2\::\quad 1$

$=\left(2\right)\left(4\right)-1+2\left(4\right)$

$\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:\left(2\right)\left(4\right)\::\quad 8$

$=8-1+2\left(4\right)$

$\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\left(4\right)\::\quad 8$

$=8-1+8$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:8-1+8\::\quad 15$

$=15$

Therefore,

$ab-c^2+2b=\left(2\right)\left(4\right)-\left(1\right)^2+2\left(4\right)=15$

Question # 4

Given the expression

$4d^3+2e\div \:f+de$

Putting d = 2, e = 3, and f = 6 in the expression

$=4\left(2\right)^3+2\left(3\right)\div \:6+\left(2\right)\left(3\right)$

Follow the PEMDAS order of operations

$\mathrm{Calculate\:exponents}\:\left(2\right)^3\::\quad 8$

$=4\cdot \:8+2\left(3\right)\div \:6+\left(2\right)\left(3\right)$

$\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:4\cdot \:8\::\quad 32$

$=32+2\left(3\right)\div \:6+\left(2\right)\left(3\right)$

$\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\left(3\right)\div \:6\::\quad 1$

$=32+1+\left(2\right)\left(3\right)$

$\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:\left(2\right)\left(3\right)\::\quad 6$

$=32+1+6$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:32+1+6\::\quad 39$

$=39$

Therefore,

$4d^3+2e\div \:\:f+de=4\left(2\right)^3+2\left(3\right)\div \:6+\left(2\right)\left(3\right)=39$

7 0

4 years ago

I need to find the mid point of the equation but I am not sure what points I put into the equation, since I'm not given any coor

Stella [2.4K]

the assumption being that M is the midpoint of AC, if that's the case, then M cuts AC into two equal halves, namely then AM = MC

$\bf \stackrel{AM}{x+5}=\stackrel{MC}{2x}\implies 5=x~\hfill \stackrel{AM~\hfill AM}{x+5\implies 5+5\implies 10}$

8 0

4 years ago

**<br> Write the word sentence as an inequality. A number w is greater than -4.

Irina-Kira [14]

Answer:

w>-4

hope this helps :)

5 0

3 years ago

death valey CA is 282 feet below sea levle. black mountain, KYis 750 feet above sea levle how many feet is black mountain from d

Morgarella [4.7K]

Answer:

$Distance = 1032\ ft$

Step-by-step explanation:

Given

$CA = 282\ ft$ <em>below sea level</em>

$KY = 750\ ft$ <em>above sea level</em>

Required

Determine the distance between them

The distance between them is calculated as thus:

$Distance = KY - CA$

Because CA is below sea level, it's value will be negated;

So, we have:

$Distance = 750\ ft - (-282\ ft)$

$Distance = 750\ ft + 282\ ft$

$Distance = 1032\ ft$

<em>Hence, the distance between them is 1032 feet</em>

4 0

3 years ago

What does x^2 = 17 Equal?

djyliett [7]

X will 34. hope this answer helps

5 0

3 years ago

Read 2 more answers