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olchik [2.2K]
3 years ago
14

Rebecca buy some scarves that cost five dollars each and two purses that cost 12 each The cost Rebecca’s total purchase is $39 w

hich equation can be used to find in the number of scarves that Rebecca buys
A. 5+24n=39
B.5+24=39
C. (24+5)n=39
D.24•5+n=39 ?
Mathematics
1 answer:
Fittoniya [83]3 years ago
4 0

Answer:

d.

Step-by-step explanation:

First, you want to add together the amount of money she spent on purses ($24), and then consider the amount of scarves (5+n). To solve, you would subtract 24 from 39, and then divide that answer by 5

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10x(15w-11)+12 what is it help me
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If im not wrong the answer is 150w - 98.
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3 years ago
The field archie will cover measures 100 yards long by 60 yards wide. Write an equation of the relationship the number of square
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Answer:

Whoa this is HARD but this "box" is 6000.

Step-by-step explanation: oh well :/


7 0
3 years ago
One of your friends is testing the effect of drinking coffee on the duration of cold symptoms. The common cold lasts, on average
Nonamiya [84]

Answer:

0.0930

Step-by-step explanation:

Given that one of your friends is testing the effect of drinking coffee on the duration of cold symptoms. The common cold lasts, on average, 6 days.

she tests a one-sided alternative about the population mean cold duration when drinking coffee, H0: μcoffee = 6 Ha: μcoffee < 6 She finds z = −1.68 with one-sided P-value P = 0.0465.

If hypotheses changed to two tailed as:

H_0: \mu_{coffee}  = \mu_{tea}\\H_a: \mu_{coffee}\neq \mu_{tea}

(Two tailed test)

Since we have mean difference and std error the same, test statistic would remain the same.

p value for two tailed would be = twice the p value for one tail

=2(0.0465)\\= 0.0930

6 0
3 years ago
The probability a randomly selected household owns corporate stock is 0.54. The probability a randomly selected household has no
34kurt

Answer:

30% probability a randomly selected household has no Internet access given the household owns corporate stock

Step-by-step explanation:

I am going to say that we have two events.

Event A: Owning corporate stock. So P(A) = 0.54.

Event B: Having no internet access. So P(B) = 0.3.

Since they are independent events, we can apply the conditional probability formula, which is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probabilitty of event B happening given that A happened. We want to find this.

P(A \cap B) is the probability of both events happening.

Since they are independent

P(A \cap B) = P(A)P(B) = 0.54*0.3

So

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.54*0.3}{0.54} = 0.3

30% probability a randomly selected household has no Internet access given the household owns corporate stock

8 0
3 years ago
1. Simplify the radical expression<br> √50<br><br> A. 5√2<br> B. 2√5<br> C. 5√10<br> D. 5
defon
/50 = /25•2
/25 • /2 further written as
5 • /2 simplified form

so A
6 0
3 years ago
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