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katrin2010 [14]
3 years ago
11

Ahhhhhhhhhhhhhhhhhhhhhhh someone plzzzzz help

Mathematics
2 answers:
Anit [1.1K]3 years ago
8 0

Answer:

15, 80

Step-by-step explanation:

1) I am assuming the first picture is a 90 degree angle total, because the question can't be solved without that assumption.

  90 - 75 = 15

  x = 15

2) The whole angle is 180 so 180 - 75 - 25 = CAD

  CAD = 80

Pavlova-9 [17]3 years ago
7 0

Answer:

15° and 80°

Step-by-step explanation:

for the first one since its a right angle then its equal to 90 degrees

90-75 = 15     x=15°

for the second one since the line is a straight line then put it equal to 180

25+75+x=180

100+x=180

x=80°      

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Dovator [93]
15 minutes= 2 problems
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3 years ago
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To convert 58.58 to a fraction, we evaluate 58.58-0.58 What is 58.58-0.58 ?
lord [1]

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58

Step-by-step explanation:

58.58 - 0.58 = 58

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How do I find the properties of a parabola
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4 years ago
gina has 250 in her saving account she puts in 4% of her monthly paycheck of 3,100 each month rodger has 350 in his savings acco
Sidana [21]

<u>Answer:</u>

3 months

<u>Explanation: </u>

Amount saved in Gina’s saving account= 250

Amount Gina puts  in her account each month= 4% of 3100

=\frac{4}{100} \times 3100

= 4 × 31

= 124

Hence total amount  added in each month =124

Therefore money credited x months

= 250 + 124 x

Amount saved in Rodger’s account = 350

Amount Rodger puts in his account each month = 3% of 2900

=\frac{3}{100} \times 290

=87

Hence total amount added in each month = 87

Therefore money credited x months

=350 + 87 x

Now to calculate the nearest month when Gina have more in her account than Rodger does

=Amount of money credited in x months in Gina’s account ≥  Amount of money credited in x months in Rodger’s account

=250+124 x ≥ 350+87 x

=37 x≥100

= x≥2.78

=3

3 0
4 years ago
Find the first , fourth , and eighth terms of the sequence A(n) = -3 •2 ^x - 1
Usimov [2.4K]

Answer:

A(1) = -7

A(4) = -48

A(8) = -769

Step-by-step explanation:

A(n) = -3.2 ^n - 1.....(1)\\\\Plug \: n= 1\: in \: (1)\\A(1) = -3.2 ^1 - 1 =-3.2-1= -6 -1  \\\huge\red{\boxed{A(1) = -7}}\\\\Plug \: n= 4\: in \: (1)\\A(4) = -3.2 ^4 - 1 =-3.16-1= -48 -1  \\\huge\purple{\boxed{A(4) = -49}}\\\\Plug \: n= 8\: in \: (1)\\A(8) = -3.2 ^8 - 1 =-3.256-1= -768 -1 \\\huge\orange{\boxed{A(8) = -769}}

5 0
4 years ago
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