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Anuta_ua [19.1K]
2 years ago
6

Does anyone the answer to that? if so please ANSWER FAST THANK YOU!!

Mathematics
1 answer:
mina [271]2 years ago
8 0
Answer is 18 do you need work shown
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The diagram below shows a shaded parallelogram drawn inside a rectangle. Using Pythagoras, find the hypotenuse of triangle A and
Julli [10]

Answer: 5.9 cm for both triangles.

Step-by-step explanation:

Hi, since the situation forms 2 right triangles we have to apply the Pythagorean Theorem:  

c^2 = a^2 + b^2  

Where c is the hypotenuse of a triangle (the longest side of the triangle) and a and b are the other sides.  

Replacing with the values given:  

c^2 = 3^2 + 5^2  

c^2 = 9+25

c^2 = 34

c = √34

c = 5.9 cm

Since both triangles are identical ( same side lengths) the hypotenuse is the same for both, 5.9 cm.

Feel free to ask for more if needed or if you did not understand something.  

5 0
3 years ago
What is the exponents <br>​
zmey [24]
The exponent of a number says how many times to use the number in a multiplication.

For Example, In 8² , the 2 is the number of times 8 has to be multiplied. In this case It has to multiplied by itself 2 times, 8x8 = 64 so 8² = 64.
Another example is 9³ since the number above is 3 we have to multiply 9 three times, 9x9x9 = 729 which means 9³ = 729.

Hope this helps
3 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!
olga55 [171]
I believe the answer is 45.
6 0
3 years ago
Read 2 more answers
Is 2/8 greater or less than 1/4
Alex17521 [72]
Its neither 2/8 is 1/4 simplified, therefore 2/8 is = 1/4 

Hope this helped!
4 0
3 years ago
Read 2 more answers
DATA ANALYSIS AND STATISTICSProbabilities involving two rolls of a dieAn ordinary (falr) die is a cube with the numbers 1 throug
Zepler [3.9K]

Solution

The table below is the required sample space of the to fair die

From the above table

The sample space contain 36 outcomes

Event A: The sum is greater than 9

we will look at the table and count all the elements that are greater than 9

There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)

The probability for event A will be

\begin{gathered} p(A)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(A)=\frac{6}{36} \\ p(A)=\frac{1}{6} \end{gathered}

P(A) = 1/6

Event B: The sum is an even number.

We will look at the table and count the number of elements that are even

There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)

The probability for event B will be

\begin{gathered} p(B)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(B)=\frac{18}{36} \\ p(B)=\frac{1}{2} \end{gathered}

p(B) = 1/2

5 0
1 year ago
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