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alekssr [168]
2 years ago
7

If a rectangular piece of paper, the dot is the midpoint of the diagonal AC, Point E on the edge of BC, fold △ DCE along the lin

e DE so that point C falls on the diagonal AC at point F. Join DF, EF. If MF = AB, then DAF =? degree​
Mathematics
1 answer:
OLga [1]2 years ago
7 0

Answer:

g sec got it thanks I will send you are not able to go to do it thanks I have to choose between us and virtual hu ki me ur name h

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Can u help me with this
Tanzania [10]
1. x^2 + x - 90

2. (x+10)(x-1)

3. x= -10 and 1
4 0
3 years ago
Read 2 more answers
the snake slithered 2.25 m before resting on a rock. Then the snake slithered twice as far as it did before, to catch a rat. Whe
NemiM [27]

Answer:

Step-by-step explanation:

2.25m + 2(2.25m) + 90 cm =

2.25m + 4.50m + 90 cm

6.75m + 90 cm

1 cm = 0.01m...so 90 cm = 90 * 0.01 = 0.9m

6.75m + 0.9m = 7.65m <===

8 0
2 years ago
Read 2 more answers
Trevor has an investment worth $6,774.50. He made his only deposit in it 22 years ago. Given that the investment yields 2.7% sim
OleMash [197]
My initial answer was $2750.45, and I will show you my calculations.

Calc : 6774.5 ÷ 100 = 67.745
67.745 × 2.7 = 182.9115
182.9115 × 22 = 4024.053
6774.5 - 4024.053 = 2750.45

= $2750.45

At first I thought this was correct, but after studying my answer I realise that the amount of interest would rise as the amount of money went up, therefore my calculations are very wrong. If I work out the answer, I will get back to you, but the calculation is more complicated than I first predicted
7 0
3 years ago
Read 2 more answers
Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m2, and the area of circle
taurus [48]

Solution:

we are given that

Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.

we have been asked to find the ratio of the radius of circle Q to the radius of circle R?

As we know that

Area of the sector is directly proportional to square of radius. So we can write

Area  \  \   \alpha \ \  r^2\\ \\ \Rightarrow A=kr^2\\ \\ \text{where k is some proportionality constant }\\ \\ \Rightarrow \frac{A_1}{A_2}=\frac{r_1^2}{r_2^2}\\ \\  \Rightarrow \frac{r_1^2}{r_2^2}=\frac{A_1}{A_2}\\ \\  \Rightarrow \frac{r_1^2}{r_2^2}=\frac{25 \pi}{49 \pi}\\ \\  \Rightarrow \frac{r_1}{r_2}=\sqrt{\frac{25 \pi}{49 \pi}} \\ \\  \Rightarrow \frac{r_1}{r_2}=\frac{5}{7} \\


7 0
3 years ago
Read 2 more answers
The scale of a map is 1:40000. What distance on the map represents a real distance of 5km?​
Rufina [12.5K]

Answer:

0.125

Step-by-step explanation:

1=40000

x-5000

x=5000÷40000=1/8=0.125

6 0
3 years ago
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