Answer:
0.45 ft/min
Step-by-step explanation:
Given:-
- The flow rate of the gravel,
- The base diameter ( d ) of cone = x
- The height ( h ) of cone = x
Find:-
How fast is the height of the pile increasing when the pile is 10 ft high?
Solution:-
- The constant flow rate of gravel dumped onto the conveyor belt is given to be 35 ft^3 / min.
- The gravel pile up into a heap of a conical shape such that base diameter ( d ) and the height ( h ) always remain the same. That is these parameter increase at the same rate.
- We develop a function of volume ( V ) of the heap piled up on conveyor belt in a conical shape as follows:
- Now we know that the volume ( V ) is a function of its base diameter and height ( x ). Where x is an implicit function of time ( t ). We will develop a rate of change expression of the volume of gravel piled as follows Use the chain rule of ordinary derivatives:
- Determine the rate of change of height ( h ) using the relation developed above when height is 10 ft:
First,, you would take the 56 two pointers the team made and multiply 56 by 2 to find out how many actual points the team made with just the 2 pointers
56 x 2 = 112
Then,, you will subtract 112 from 146 to see how many points are left
146 - 112 = 34
That shows that 112 of the points came from 2 pointers and 34 came from 3 pointers :)
Answer:
the second i think i dont know for sure
If you have 20 square<span> pieces of wood, describe all the different ways you could make a rectangle by placing them side by side.</span><span>
1X20, 2X10, 4X5</span>