Answer: 120 ways
Step-by-step explanation:
Let's label the routes a, b, c, d, and e. The goal is to come up with as many unique permutations as possible.
1 route: a=1. one factorial (1!) =1*1=1
2 routes: ab, ba=2. 2!=1*2=2
3 routes: abc, acb, bac, bca, cab, cba=6. 3!=1*2*3=6
4 routes: 4!=1*2*3*4=24
5 routes: 5!=1*2*3*4*5=120 ways
I believe the answer would be 700 paintings
wowza that’s a lot of paintings!
Answer:
option C
Step-by-step explanation:
to find the solution for the equation 4x + 2 = x + 3, graph the equations
y= 4x+2 and y=x+3
Lets make a table for each equation
x y= 4x+2
-1 4(-1) + 2= -4+2 = -2
0 4(0) + 2= 2
1 4(1) + 2= 6
plot all the points on graph
Lets make table for second equation
x y= x+3
-1 -1+3 = 2
0 0+3 = 3
1 1+3 = 4
Plot the point on the graph and make a line
option C is correct
Answer:
y=x-1/y
Step-by-step explanation:
x=2y+1
x-1=2y
y=x-1/y
Answer:
y=-3x+3
Step-by-step explanation:
hope this helps :)
