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julia-pushkina [17]

3 years ago

10

QUIL - Level G p) The total cost of a pizza and 3 drinks is $19. The price of the pizza is $10 and each drink is the same price,

d. 0) Which model represents the situation? 10 d d d 19 What is the price of one drink?

1 answer:

garri49 [273]3 years ago

4 0

Answer:

a

Step-by-step explanation:

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Step-by-step explanation:

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3(32 − 4 + 6 )− (82 + + 3) ?<br> simpilyfy<br> plzz

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3 years ago

Read 2 more answers

a woman is 10 times as old as her daughter. In 8 years she will be 4 times as old as her daughter. How okd is her mother now?

Bond [772]

Answer:

48 yr. old

Step-by-step explanation:

Assume daughter is 4 and mom is 10 times her age, so mom is 40.

10 (woman) * 4 (daughter's age) = 40 yr. old mom

Present day...

40 (yr old mom) + 8 (yrs later) = 48 yr. old mom today

4 (yr old daughter) + 8 (yrs later) = 12 yr. old daughter today

So, if mom is 4 times as her daughter's age today...

48 (yr. old mom) / 12 (yr. old daughter) = 4

5 0

2 years ago

Sloan [31]

Answer:

<h3>#1</h3>

<u>Rectangle area:</u>

A = lw

<u>Given:</u>

l = 12 ft, A = 300 ft²

<u>Find w:</u>

12w = 300
w = 300/12
w = 25 ft

<h3>#2</h3>

<u>Perimeter is the sum of side lengths:</u>

P = 2 1/4 + 5 2/5 + 5 17/20 =

2 + 5 + 5 + 1/4 + 2/5 + 17/20 =

12 + 5/20 + 8/20 + 17/20 =

12 + 30/20 =

12 + 1.5 =

13.5 ft

<h3>#3</h3>

Cost of a shirt = $19.99
Number of shirts = 6

<u>Total cost:</u>

$19.99*6 = $119.94

8 0

3 years ago

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

3 0

3 years ago