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2 years ago

13

PLEASE HELPP ME IT"s DUE TODAY!!!!!

1 answer:

pishuonlain [190]2 years ago

5 0

Answer:

since -5 and -5 are the same number, they are on the same y axis so the only distance we need to calculate is between the X coordinates

so when looking for distance you can not have a negative what |-3|+|9| is looking for is the distance from 0 on the X axis since distance can't be negative, (you go 3 miles away from your house in one direction, vs 3 miles in the opposite both ways is positive, even with opposite directions same with axis, it doesnt matter which way, only the number.) you need the absolute value of -3 to get the distance from the 0 on the x axis

short version: distance is positive and its adding the distances from the x axis to get distance from each other

Step-by-step explanation:

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Solve the formula for <br> c. show your steps. p = r - c

d1i1m1o1n [39]

P=r-c
p-r= r-r-c
p-r=-c
(p-r=-c) ^{-1}
-p+r=c

4 0

3 years ago

Solve.<br> -15 - (-8) - (-23) – 46<br> Your answer

Evgen [1.6K]

Answer:

-30

Step-by-step explanation:

-15 - (-8) - (-23) – 46

When u have 2 negatives it will always make a positive -(-)

<u><em>-15 + 8 </em></u>+ 23 - 46

<u><em>-7 + 23 </em></u>- 46

<u><em>16 - 46</em></u>

-30

Hope this helped!

Have a supercalifragilisticexpialidocious day!

6 0

3 years ago

If k= am + 3mx, the value of m in terms of a, k, and x can be expressed as

soldier1979 [14.2K]

K=am+3mx
K=m(a+3x)
m=K/(a+3x)

Answer: m=K/(a+3x)

8 0

3 years ago

Read 2 more answers

Need help on this question

miss Akunina [59]

If you divide the first equation by 2 and the second by 3, you get

$4x+3=y\\4x-1=y$

These equations differ only in their y-intercept, so describe parallel lines. The appropriate choice is ...

... H The lines are parallel.

7 0

3 years ago

How many different strings of length 12 containing exactly five a's can be chosen over the following alphabets? (a) The alphabet

N76 [4]

Answer:

Part (A) The required ways are 792.

Part (B) The required ways are 101376.

Step-by-step explanation:

Consider the provided information.

Part (A) The alphabet {a, b}

The length of strings is 12 that containing exactly five a's.

The number of ways are: $\frac{12!}{5!7!}$

After filling "a" we have now 7 places.

For 7 places we have "a" and "b" alphabet but we already select a's so now the remaining place have to fill by "b" only.

Thus, the required ways are: $\frac{12!}{5!7!}\times 1=792$

Part (B) The alphabet {a, b, c}

We have selected five a's now we have now 7 places.

For 7 places we have "b" and "c".

Thus, there are 2 choices for each 7 place that is $2^7$

Therefore the total number of ways are: $792\times 2^7=101376$

Thus, the required ways are 101376.

7 0

4 years ago