Term to be added is: + 121/4
t^2 + 11t + 121/4
(t + 11/2) (t + 11/2)
Answer:
a) $50,880
b) $48
c) 1060
Step-by-step explanation:
a)
-320x^2 + 1920x + 48000 = 0
This is a parabola that opens downward. It has a maximum value. The maximum value occurs at x = -b/(2a)
x = -b/(2a) = (-1920)/(2(-320)) = 1920/640 = 3
The maximum revenue, y, is the value of the function evaluated at x = 3.
f(x) = -320x^2 + 1920x + 48000
f(-3) = -320(3)^2 + 1920(3) + 48000
f(-3) = 50,880
The maximum revenue is $50,880
b)
Since maximum revenue occurs at x = 3, and since x represents the number of $4 discounts, the discount is 3 * $4 = $12. The price is $60 - $12 = $48
c)
$50,880/$48 = 1060
5x - 3y = 15
5x - <u>5x</u> -3y = <u>- 5x</u> + 15
<u>-3y</u> = <u>-5x</u> + 15
3y = 5x - 15
divide all of them by 3...
y = 5/3 - 5
There are no solutions.<span>
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