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2 years ago

6

Which two charges have a sum of 0?

2 answers:

Llana [10]2 years ago

4 0

Answer:

The second one and the fourth one :)

n200080 [17]2 years ago

3 0

2 and 4 because they are canceling each other out.

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Louis was served 145 g of meat

tamaranim1 [39]

What is the rest of the question

5 0

3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago

algol [13]

Answer:jio

Step-by-step explanation:

6 0

1 year ago

a researcher in a personal submarine begins at the surface of thr ocean. The submarine descends 20.6 meters and the ascends 5 7/

Mumz [18]

Answer:

$Depth = 14.9\ metres$

Step-by-step explanation:

Given

$Desc = 20.6\ metres$

$Asc = 5\frac{7}{10}\ metres$

Required

Determine the depth

The depth is the distance between the two distances as follows'

$Depth = |Desc - Asc|$

Substitute values

$Depth = |20.6 - 5\frac{7}{10}|$

Convert fraction to decimal

$Depth = |20.6 - 5.70|$

$Depth = |14.9|$

$Depth = 14.9\ metres$

6 0

2 years ago

What is a function please help

maksim [4K]

Answer:

A function has no x values repeated twice.

6 0

2 years ago