Triangle XYZ was dilated by a scale factor of 2 to create triangle ACB and cos ∠X = 2 and 5 tenths over 5 and 59 hundredths.
1 answer:
Based on the above, the Triangle XYZ and ACB are known to be similar triangles since tanX = tanA = 5 over 2 and 5 tenths;
Hence:
- AC = 2 x XY
- CB = 2 x YZ
From the question given; Triangle XYZ is known to have been dilated by a scale factor of 2 to form a type of triangle known as triangle ACB, So therefore, XYZ and ACB are known to be the same or similar triangles.
Since Angles Y and C are known to both measure 90 degrees, and angles A and X are said to be congruent. Therefore:
tanX = tanA = 5 over 2 and 5 tenths
AC = 2 x XY
CB = 2 x YZ
For part B:
cosX=Base/Hypotenuse
cos A=AC/AB
AC = 2.05
AB = 5.59
Therefore, Based on the above, the Triangle XYZ and ACB are known to be similar triangles since tanX = tanA = 5 over 2 and 5 tenths;
Hence:
- AC = 2 x XY
- CB = 2 x YZ
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Answer:
Range is {y | y ≥ –11}
Step-by-step explanation:
This is quadratic equation.
<em>A quadratic equation's range can be found if we find the vertex.</em>
For quadratic equations that have a positive number in front of , it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>
The formula for vertex of a parabola is:
Vertex =
Where,
is the coefficient of
is the coefficient of
From our equation given, and
Now, coordinate of vertex is
coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the
value [
] into the equation. So we have:
Hence, the range would be all numbers greater than or equal to
Third answer choice is the right one.