Answer:
2678.06
Step-by-step explanation:
Annual is once every year and 3.5% of 2,500.00 is
3.5% ×2,500.00 = 87.5
so in the first year Deirdre has 2500.00 + 87.5 = 2587.5
then you find 3.5% of 2587.5 which is 90.56250000000001
but since it's money we round it to 90.56
2587.5+90.56= 2678.06
The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
Read more about exponential functions at:
brainly.com/question/2456547
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Answer:
Step-by-step explanation:
550 48 6-0 3/16 3/16 800
1000 48 10-10 3/16 3/16 1300
1100 48 11-11 3/16 3/16 1400
1500 48 15-8 3/16 3/16 1650
65 9-0 3/16 3/16 1500
2000 65 11-10 3/16 3/16 2050
2500 65 14-10 3/16 3/16 2275
3000 65 17-8 3/16 3/16 2940
4000 65 23-8 3/16 3/16 3600
5000 72 23-8 1/4 1/4 5800
84 17-8 1/4 1/4 5400
7500 84 26-6 1/4 1/4 7150
96 19-8 1/4 1/4 6400
10000 96 26-6 1/4 5/16 8540
120 17-0 1/4 5/16 8100
12000 96 31-6 1/4 5/16 10500
120 20-8 1/4 5/16 9500
15000 108 31-6 5/16 5/16 13300
120 25-6 5/16 5/16 12150
20000 120 34-6 5/16 5/16 15500
25000 120 42-6 3/8 3/8 22300
30000 120 51-3 3/8 3/8 28000
Answer:
24.5
Step-by-step explanation: