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Yakvenalex [24]
3 years ago
5

Classify the triangle by its angle measures.

Mathematics
1 answer:
Orlov [11]3 years ago
5 0

Answer:

d) Acute

Step-by-step explanation:

if all three angle measures are less than 90 degrees, the triangle is acute

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The average daily jail population in the United States is 706,242. If the distribution is normal and the standard deviation is 5
Karolina [17]

a. The probability that on a randomly selected day, the jail population

is greater than 750,000 is 20.1%

b. The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Step-by-step explanation:

The given is:

1. The average daily jail population in the United States is 706,242

2. The distribution is normal and the standard deviation is 52,145

3. We need to find the probability that on a randomly selected day,

    the jail population is greater than 750,000

4. We need to find the probability that on a randomly selected day,

    the jail population is between 600,000 and 700,000

a.

At first find z-score

∵ z = (x - μ)/σ, where x is the score, μ is the mean and σ is the standard

   deviation

∵  x = 750,000 , μ = 706,242 and σ = 52,145

∴ z = \frac{750,000-706,242}{52,145} ≅ 0.84

Use the normal distribution table of z to find the area to the right of

the z-value

∵ The corresponding area to z-score of 0.84 is 0.79955

- But we are interested in x > 750,000, we need the area to the

  right of z-score

∴ P(x > 750,000) = 1 - 0.79955 = 0.2005

∴ P(x > 750,000) = 0.2005 × 100% = 20.1%

The probability that on a randomly selected day, the jail population is

greater than 750,000 is 20.1%

b.

We will find z-score for 600,000 < x < 700,000

∵ z = \frac{600,000-706,242}{52,145} ≅ -2.04

∵ z = \frac{700,000-706,242}{52,145} ≅ -0.12

Use the normal distribution table of z to find the area between

the two z-values

∵ The corresponding area to z-score of -2.04 is 0.02068

∵ The corresponding area to z-score of -0.12 is 0.45224

- To find P(600,000 < x < 700,000) subtract the two values above

∴ P(600,000 < x < 700,000) = 0.45224 - 0.02068 = 0.4316

∴ P(600,000 < x < 700,000) = 0.4316 × 100% = 43.2%

The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Learn more:

You can learn more about z-score in brainly.com/question/7207785

#LearnwithBrainly

5 0
3 years ago
Which number sets (i.e. Natural, Whole, Integer, Rational, Real, etc.) are best suited to represent discrete functions? Why? Whi
Dahasolnce [82]

Answer:

e

Step-by-step explanation:

4 0
3 years ago
The Graduate Management Admission Test (GMAT) is a standardized exam used by many universities as part of the assessment for adm
IgorC [24]

Answer:

16.7% of GMAT scores are 647 or higher

Step-by-step explanation:

The Empirical Rule states that 68% of the values are within 1 standard deviation of the mean(34% above, 34% below). It also considers that 50% of the values are above the mean and 50% are below the mean.

In this problem, we have that the mean \mu is 547 and that the standard deviation \sigma is 100.

a. What percentage of GMAT scores are 647 or higher?

647 is 1 standard deviation above the mean.

So, 50% of the values are below the mean. Those scores are lower than 647.

Also, there is the 34% of the values that are above the mean and are lower than 647.

So, there is a 50% + 34% = 84% percentage of GMAT scores that are 647 or lower.

The sum of the probabilities must be 100

So, the percentage of GMAT scores that are 647 or higher is 100% - 84% = 16%.

3 0
2 years ago
HELP PLEASE I"LL GIVE 18 POINTS
Vladimir79 [104]
Times the two to get your answer.
3 0
3 years ago
Read 2 more answers
the number of three-digit numbers with distinct digits that be formed using the digits 1,2,3,5,8 and 9 is . The probability that
jolli1 [7]

Answer:

a)120

b)6.67%

Step-by-step explanation:

Given:

No. of digits given= 6

Digits given= 1,2,3,5,8,9

Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be

6P3= 6!/3!

      = 6*5*4*3*2*1/3*2*1

      =6*5*4

      =120

Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:

As the first and last digits can only be even

then the form of number can be

a)2n8 or

b)8n2

where n can be 1,3,5 or 9

4*2=8

so there can be 8 three-digit numbers with both the first digit and the last digit even numbers

And probability = 8/120

                          = 0.0667

                          =6.67%

The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !

5 0
3 years ago
Read 2 more answers
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