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3 years ago

If θ is in Quadrant III and sinθ = -3/5, then cosθ = _____.

1 answer:

4 0

Because the angle omega is in QIII, the adjacent side lies to the left of the origin and thus is represented by a negative value. Since sin omega = -3/5, the opposite side is also negative. Use the Pythagorean Theorem to obtain the length of the adjacent side: 5^2 = (-3)^2 + x^2, or 25 = 9 + x^2, or x^2 = 16.

Solving for x: x = plus or minus 4. Since we are in QIII, let x = -4.

Then cos omega is opp / hyp, or -4/5.

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Answer:

152°

Step-by-step explanation:

Let P be any point on tangent $\overleftrightarrow{YZ}$ and WY is secant or chord of the $\odot J$ .

$\therefore m\angle WYZ + m\angle WYP = 180°\\(Straight \: line \: \angle 's) \\\therefore 104° + m\angle WYP = 180°\\\therefore m\angle WYP = 180°- 104° \\\red{\boxed {\bold {\therefore m\angle WYP = 76°}}} \\$

NOW, by tangent secant theorem:

$m\angle WYP =\frac{1}{2}\times m(\widehat{WXY}) \\\\76°=\frac{1}{2}\times m( \widehat{WXY}) \\\\76°\times 2 =m( \widehat{WXY}) \\\huge \purple {\boxed {\therefore m(\widehat{WXY}) = 152°}}$

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3 years ago

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3 years ago

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