Answer:
- All four of the remaining faces will be 4 inches wide.
Step-by-step explanation:
A right rectangular prism with square base and top with sides of 4 in.
It has four sides of 4 in wide each and of equal height of unknown measure.
<u>Options:</u>
All four of the remaining faces will have a height of 4 inches.
- Incorrect, the height is unknown.
There is not enough information to tell what the other faces will look like.
- Incorrect, all the other faces are rectangular.
Two of the remaining faces will be 4 inches wide.
- Incorrect, all the faces are 4 in wide.
All four of the remaining faces will be 4 inches wide.
Remember that multiplying is how many times you add a number to itself. If you multiply by 3, you add the first number to itself 3 times.
When you multiply a given number by 1, you get the first number (it doesn't change).
When you multiply by a number less than one, say, one half, you'll end up with half of the original number --> a smaller number.
When you multiply a number by more than one, you will get a number bigger than the original because you are adding it to itself more than once. Even if it is a fraction or decimal, if it is greater than 1, then the new product will be larger than the original number.
Hope this helps! :)
Answer:
x= -1
Step-by-step explanation:
Solving through linear equation,
-0.1x + 3/10= 4/10
Bring 3/10 to the other side making it minus
-0.1x = 4/10 - 3/10
-0.1x = (4-3)/10
-0.1x= 1/10
Bring -0.1 to the other side n divide
x= 1/10 ÷ -0.1
( Note that -0.1 is the same as -1/10)
x = 1/10 ÷ -1/10
= 1/10*-10/1
= -10/10
= -1
216 divided by 3 is 72 so making the answer
1/72
<em><u>Option A</u></em>
<em><u>The solution is:</u></em>
![x = \pm 2i \sqrt{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cpm%202i%20%5Csqrt%7B2%7D)
<em><u>Solution:</u></em>
![f(x) = 19x^2+152](https://tex.z-dn.net/?f=f%28x%29%20%3D%2019x%5E2%2B152)
We have to solve the equation f(x) = 0
Let f(x) = 0
![0=19x^2+152](https://tex.z-dn.net/?f=0%3D19x%5E2%2B152)
Solve the above equation
![19x^2 + 152 = 0](https://tex.z-dn.net/?f=19x%5E2%20%2B%20152%20%3D%200)
![\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8](https://tex.z-dn.net/?f=%5Cmathrm%7BSubtract%5C%3A%7D152%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D%5C%5C%5C%5C19x%5E2%2B152-152%3D0-152%5C%5C%5C%5CSimplify%5C%20the%5C%20above%5C%20equation%5C%5C%5C%5C19x%5E2%20%3D%20-152%5C%5C%5C%5C%5Cmathrm%7BDivide%5C%3Aboth%5C%3Asides%5C%3Aby%5C%3A%7D19%5C%5C%5C%5C%5Cfrac%7B19x%5E2%7D%7B19%7D%20%3D%20%5Cfrac%7B-152%7D%7B19%7D%5C%5C%5C%5Cx%5E2%20%3D%20-8)
Take square root on both sides
![x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cpm%20%5Csqrt%7B-8%7D%5C%5C%5C%5Cx%20%3D%20%5Cpm%20%5Csqrt%7B-1%7D%5Csqrt%7B8%7D%5C%5C%5C%5C%5Cmathrm%7BApply%5C%3Aimaginary%5C%3Anumber%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%7B-1%7D%3Di%5C%5C%5C%5Cx%20%3D%20%5Cpm%20i%5Csqrt%7B8%7D%5C%5C%5C%5Cx%20%3D%20%5Cpm%20i%20%5Csqrt%7B2%20%5Ctimes%202%20%5Ctimes%202%7D%5C%5C%5C%5Cx%20%3D%20%5Cpm%202i%5Csqrt%7B2%7D)
Thus the solution is found