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2 years ago

A circle has a circumference of 10 feet. What is the diameter?

Mathematics

2 answers:

arsen [322]2 years ago

7 0

The diameter would be 3.18

zloy xaker [14]2 years ago

6 0

Um the diameter would be 3.18

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When u round to the nearest hundred thousand the population of the state of North Carolina is 9,800,000. Which could be the exac

rjkz [21]

Answer:

D - 9,848,060

Step-by-step explanation:

In the number 9,848,060 the number 8 is in the hundred thousands place.

The number behind it is 4, which is nor equal to or more than 5, meaning that that the 8 stays the same.

6 0

3 years ago

Please help, much appreciated, will give brainliest :)

DIA [1.3K]

Answer:

so if you multiple4.8 percent by 3,000 u get 144 and then u divide by 3 and that u u 48 dollars per year

7 0

3 years ago

Leslie needs 324 inches of fringe to put around the edge of a tablecloth.The fringe comes in lengths of 10 yards.Of Leslie buys

Delicious77 [7]

324 inches = 27 feet.

10 yards = 30 feet

30 - 27 = 3.

Final answer: 3 feet of fringe will be left over.

P.S, could you mark this the brainly answer? :)

3 0

3 years ago

How many drinks are in 3 7 ounces glasses of wine

Ray Of Light [21]

Answer:

1 'standard' drink usually refers to 5 ounces of wine (with 12% alcohol)

So 37 ounces will be 37/5 = 9 and 1/4 drinks

5 0

2 years ago

Read 2 more answers

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5? Quadratic formula: x = StartFracti

weqwewe [10]

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$ and $x=\frac{-2+\sqrt{19}}{3}$

Step-by-step explanation:

The quadratic formula of the quadratic equation ax² + bx + c = 0, is

$x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}$

To find the solution of the quadratic equation by using quadratic formula

Find the values of a, b, and c from the quadratic equation
Substitute these values in the quadratic formula
Calculate the values of x

∵ -3x² - 4x + 5 = 0

∴ a = -3 , b = -4 and c = 5

- Substitute these values in the quadratic formula

∵ $x=\frac{-(-4)+\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4+\sqrt{16+60}}{-6}$

∴ $x=\frac{4+2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2-\sqrt{19}}{3}$

∵ $x=\frac{-(-4)-\sqrt{(-4)^{2}-4(-3)(5)}}{2(-3)}$

∴ $x=\frac{4-\sqrt{16+60}}{-6}$

∴ $x=\frac{4-2\sqrt{19}}{-6}$

- Simplify by dividing up and down by -2

∴ $x=\frac{-2+\sqrt{19}}{3}$

The solutions of the quadratic equation 0 = -3x² - 4x + 5 are

$x=\frac{-2-\sqrt{19}}{3}$ and $x=\frac{-2+\sqrt{19}}{3}$

Learn more:

You can learn more about quadratic equation in brainly.com/question/7361044

#LearnwithBrainly

9 0

3 years ago

Read 2 more answers