Answer:
Q (2.5, -4)
Step-by-step explanation:
Let A (1, -5), C = (10, 1), find Q (x, y), so that AQ:QC = 1:5
AQ = (x - 1, y + 5)
QC = (10 - x, 1 - y)
AQ:QC = 1:5
so 5*AQ = QC
5(x - 1) = (10 - x)
5(y + 5) = 1 - y
Solve them:
5x - 5 = 10 - x
6x = 15
x = 15/6 = 2.5
5y + 25 = 1 - y
6y = -24
y = -24/6 = -4
Then answer is Q (2.5, -4)
(t^2+1)^100
USE CHAIN RULE
Outside first (using power rule)
100*(t^2+1)^99 * derivative of the inside
100(t^2+1)^99 * d(t^2+1)
100(t^2+1)^99 * 2t
200t(t^2+1)^99
Answer:
subtract 2x on both sides
Step-by-step explanation:
Answer:
i8765
Step-by-step explanation:
Answer:
81
Step-by-step explanation:
Sorry this question does not sense..... 81 is evaluated
maybe I don't understand the terminology
