Answer:
y = (1/3)x - 1
Step-by-step explanation:
The product of the slopes of perpendicular lines is -1. That makes the slopes of perpendicular lines negative reciprocals. Since line p has slope -3, the slope of line t is 1/3. Also, line t passes through point (9, 2).
y = mx + b
m = slope
y = (1/3)x + b
Now we replace x and y with the x- and y-coordinates of the given point, respectively, and we solve for b.
2 = (1/3)(9) + b
2 = 3 + b
b = -1
Now we replace b with -1.
y = (1/3)x - 1
The ordered pairs that make this equation true is (4, 10)
A linear equation is given by:
y = mx + b;
where y, x are variables, m is the slope of the line and b is the y intercept.
Given the linear equation: y = 10x - 30:
At (1, -12): y = 10(1) - 30 = -20 ≠ -12
At (8, 1): y = 10(8) - 30 = 50 ≠ 1
At (4, 10): y = 10(4) - 30 = 10
At (6, 20): y = 10(6) - 30 = 30 ≠ 20
The ordered pairs that make this equation true is (4, 10)
Find out more at: brainly.com/question/13911928
Since the traversal intersects two parallel lines, the corresponding angles are congruent. Set both expressions equal to each other and you get x=6
N = 5m
n = m + 36
since n is equal to both the expression in m we can say:-
5m = m + 36
4m=36
m = 9
and n = 5*9 = 45
