Answer:
a) 91% of the scores were at or below her score.
b) 9% of the scores were above her score.
Step-by-step explanation:
When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.
In this problem, we have that:
Angela scored on the 91st percentile.
(a) What percentage of the scores were at or below her score?
Since Angela scored on the 91st percentile, 91% of the scores were at or below her score.
(b) What percentage were above?
Since Angela scored on the 91st percentile, 9% of the scores were above her score.
The measured data is
x=[10.56, 9.52, 9.73, 9.80, 9.78, 10.91].
Calculate the mean.
m = (10.56+9.52+9.73+9.80+9.78+10.91)/6 = 10.05
Calculate the deviations from the mean.
k = x - m
= [0.51, -0.53, -0.32, -0.25, -0.27, 0.86]
Calculate the absolute deviation from the mean.

Answer: 0