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marshall27 [118]
3 years ago
10

When Marie solved a system using substitution, she got 0 = 0. What can Marie conclude? The system of equations does not have a s

olution. The work must be incorrect because it is not possible to get this equation. The solution to the system is (0, 0). The system of equations has infinitely many solutions.
Mathematics
1 answer:
scZoUnD [109]3 years ago
7 0

Answer:

ok

Step-by-step explanation:

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What is the measure of ∠L?
otez555 [7]
<h3>Answer:  72.54</h3>

====================================================

Explanation:

We set up a cosine ratio, since we want to connect the adjacent and hypotenuse. Then we'll use the inverse cosine, which is also known as arccosine, to isolate the angle value.

This is what your steps could look like:

cos(angle) = adjacent/hypotenuse

cos(L) = LM/LN

cos(L) = 18/60

cos(L) = 0.3

L = arccos(0.3)

L = 72.542396876278 which is approximate

L = 72.54 degrees approximately

Make sure your calculator is in degree mode.

8 0
3 years ago
Write a word problem using the equation -4-10
Nata [24]
If you were to borrow $4 from one person and you borrow $10 more from another person. How much do you owe altogether?

5 0
4 years ago
50 points for this!!!!!
Alex
I think that they’re all true except for the last statement.
7 0
3 years ago
Read 2 more answers
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
xeze [42]
X = advance 
y= same day 

x+y=70

30x+15y=1650

--------------------------
  30x+15y=1650    
- x+y=70               (x15) -> 15x+15y=1050
--------------------------
 30x+15y=1650 
-15x+15y=1050
--------------------------
15x=600
x=600/15
x=40


so now u can insert the price of x AKA the price of the advanced ticket to find our the price of the same day ticket. 

x+y=70
so 
 40+ y=70 
y=70-40
y=30


x = advance =40
y= same day =30





8 0
3 years ago
Show that the following argument with hypotheses on lines 1–2 and conclusion on line c is
Sonja [21]

Answer:

Step-by-step explanation:

p \Rightarrow q \equiv (\neg p \vee q) [logical equivalence]

\neg (q \vee r) \equiv (\neg q \wedge \neg r) [morgan laws]

if (\neg q \wedge \neg r) is true, then \neg q is true and \neg r is too.

with \neg q true, then q is false [double denial]

In the first equivalence it follows that \neg p is true [identity law]

Then it can be concluded that \neg p

7 0
3 years ago
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