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stira [4]
3 years ago
6

Is 5 m, 20 m, 25 m a right triangle

Mathematics
2 answers:
vlabodo [156]3 years ago
6 0

Answer:

No

Step-by-step explanation:

We can check this using the Pythagorean Theorem, a^{2} + b^{2}  = c^{2}.

First, we can plug our two smaller sides in for a and b, and the largest side in for c.,

5^{2} + 20^{2} = 25^{2}

Next, we can check the left side of the equation, which we find to be:

5^{2} = 25\\20^{2} = 400\\

Then, we can add these products and achieve the result of 425

Finally, we can solve the right side of the equation, which equals 625

As 425 ≠ 625, this equation fails the Pythagorean Theorem, and is therefor false.

Yuliya22 [10]3 years ago
3 0

Answer:

NO

Step-by-step explanation:

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Answer/Step-by-step explanation:

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Since a Pythagorean triple is three positive integers a, b, and c such that (a^2)+(b^2)=(c^2), first take the sum of the squares of the two legs and make an estimate. For example, 3, 4, and 5 is a Pythagorean triple since 9+16=25

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Answer:

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Step-by-step explanation:

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{3x}^{2}  - 5x =  - 8 \\  {3x}^{2}  - 5x + 8 = 0

This equation has the next form:

{ax}^{2}  + bx + c = 0

To find if the equation has two complex solutions we have to check if the discriminant is negative, as follows:

{b}^{2}  - 4ac \\ ( { - 5})^{2}  - 4 \: . \: 3 \: . \: 8 = 25 - 96 =  - 71 < 0

Then, the first case has two complex solutions.

In the second case,

{2x}^{2}  = 6x - 5 \\  {2x}^{2}  - 6x + 5 = 0

The discriminant in this case is:

( { - 6})^{2}  - 4 \: . \: 2 \: . \: 5 = 36 - 40 =  - 4 < 0

Then, the second case has two complex solutions.

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12x =  {9x}^{2}  + 4 \\  { - 9x}^{2}  + 12x - 4 = 0

The discriminant in this case is:

{12}^{2}  - 4 \: . \: ( - 9) \: . \: ( - 4) = 144 - 144 = 0

Then, the third case has two real solutions.

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{ - x}^{2}  - 10x = 34 \\  { - x}^{2} - 10x - 34 = 0

The discriminant in this case is:

( { - 10})^{2}  - 4 \: . \: ( - 1) \: . \: ( - 34) = 100 - 136 =  - 36 < 0

Then, the fourth case has two complex solutions.

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