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stira [4]
3 years ago
6

Is 5 m, 20 m, 25 m a right triangle

Mathematics
2 answers:
vlabodo [156]3 years ago
6 0

Answer:

No

Step-by-step explanation:

We can check this using the Pythagorean Theorem, a^{2} + b^{2}  = c^{2}.

First, we can plug our two smaller sides in for a and b, and the largest side in for c.,

5^{2} + 20^{2} = 25^{2}

Next, we can check the left side of the equation, which we find to be:

5^{2} = 25\\20^{2} = 400\\

Then, we can add these products and achieve the result of 425

Finally, we can solve the right side of the equation, which equals 625

As 425 ≠ 625, this equation fails the Pythagorean Theorem, and is therefor false.

Yuliya22 [10]3 years ago
3 0

Answer:

NO

Step-by-step explanation:

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Answer:

482

Step-by-step explanation:

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a_{n} =a_{1} +(n-1)d

Where a_{1} is the first term, a_{n} is the nth term, and d is the common difference. To find the 61st term, all we need is the first term and the common difference. By looking at what given, we can say the first term is 2. Now, to find the common difference, we find the difference of a term from the term before it. In this case we can do 10-2, which is 8 , or the common difference. Since we have everything we need, it can be plugged into the equation:

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4 0
2 years ago
Find point P that divides segments AB into a 2:3 ratio.
nasty-shy [4]
\bf ~~~~~~~~~~~~\textit{internal division of a line segment}
\\\\\\
A(-3,1)\qquad B(3,5)\qquad
\qquad \stackrel{\textit{ratio from A to B}}{2:3}
\\\\\\
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-------------------------------\\\\
P=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)

\bf -------------------------------\\\\
P=\left(\cfrac{(3\cdot -3)+(2\cdot 3)}{2+3}\quad ,\quad \cfrac{(3\cdot 1)+(2\cdot 5)}{2+3}\right)
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Step-by-step explanation:

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