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marusya05 [52]
3 years ago
8

Trigonometric Ratios and Unit Circles. See Image Below.

Mathematics
1 answer:
Sophie [7]3 years ago
6 0

Answer:

irudiwhiwhs swsw is d

Step-by-step explanation:

8349240 is your aswr 213

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Write two expressions where the solution is 41.
ladessa [460]

One expression could be.... Nine times 4 plus five equals forty one. ALSO...  Eight times eight equals sixty four then subtract twenty four equals forty one
8 0
3 years ago
How many 4-digit numbers are neither multiples of 2 nor multiples of 5?
Gwar [14]

There are 10,000 total four-digit numbers (1000 through 9999).

Multiples of 2 end in 0, 2, 4, 6, and 8. There are 9*10*10*5 = 4500 four-digit multiples of 2.

Multiples of 5 end in 0 or 5. There are 9*10*10*2 = 1800 four-digit multiples of 5.

There is redundancy between the two sets of numbers, namely those that end in 0, which are both multiples of 2 and 5. There are 9*10*10*1 = 900 four-digit multiples of both 2 and 5.

Then there are 4500 + 1800 - 900 = 5400 total four-digit numbers that are either multiples of 2 or 5, which means the remaining 4600 numbers are neither multiples of 2 nor 5.

4 0
3 years ago
4x - 5y = 15<br> find the slope and y-intercept
Mazyrski [523]

Answer:

slope=4/5

y-intercept = -3

Step-by-step explanation:

first we need to rewrite the expression to

y=mx+b

were b is the y-intercept and m the slope

4x-5y=15\\\\4x-5y+5y=15+5y\\\\4x+0=15+5y\\\\4x=5(3)+5(y)\\\\4x=5(3+y)\\\\\frac{1}{5}*4x= \frac{1}{5}*5(3+y) \\\\\frac{4x}{5}=3+y\\\\\frac{4x}{5} -3=3+y-3\\\\\frac{4x}{5} -3=y+0\\\\y=\frac{4x}{5} -3\\\\y=\frac{4}{5}x-3

so there we have it

m=\frac{4}{5} \\\\b=-3

6 0
3 years ago
What are two other ways to name plane C?
svetoff [14.1K]
Answer: Other names for plane C can be plane EFG or plane EBF hope that helps (:
4 0
3 years ago
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
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