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2 years ago

The graph represents the piecewise function if

Mathematics

1 answer:

TiliK225 [7]2 years ago

8 0

Answer:

Where is the graph

Step-by-step explanation:

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2(x+3)-2(x+1)7z=3x-1 <br>which two are possible correct first steps in solving this equation ?

Svet_ta [14]

Step-by-step explanation:

first you do 3×1 get your answer and then × it by 2 then your answer you get you × it by 3 what you get - by 2 what you get you - by 1 and you get your answer hope I helped

3 0

3 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

2 years ago

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3 years ago

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The shortest distance from a point to a straight line is

Dahasolnce [82]

The shortest distance from a point to a straight line is the measurement of the line segment which connects the point to the straight line. This line segment should be perpendicular to the line and is thus called the perpendicular distance.

5 0

3 years ago

⦁ Explain how you could use the construction tool or a compass and straightedge to create a line segment that is twice as long a

lara [203]

Answer:

u can be using it at perpendicular and place it's center on point A

hope that helps a bit-

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3 years ago