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LiRa [457]
3 years ago
11

Concerned about graffiti, mayors of nine suburban communities instituted a citizen community watch program. community monthly in

cidents after monthly incidents before burr oak 4 7 elgin corners 5 8 elm grove 2 1 greenburg 3 10 huntley 4 6 north lyman 8 8 south lyman 2 6 pin oak 5 5 victorville 5 9 pictureclick here for the excel data file (a) choose the appropriate hypotheses to see whether the number of graffiti incidents declined. assume μd is the mean difference in graffiti incidents before and after.
a. h1: μd ≤ 0 versus h0: μd > 0.
b. h0: μd ≥ 0 versus h1: μd < 0. a b

Mathematics
1 answer:
lesya [120]3 years ago
3 0
The data are reported in the attached table.

We define the null hypothesis H₀ as the statement that is believed true until we prove it wrong with the test.
We define the alternative hypothesis H₁ as the statement we want to conclude with our test.

The difference in graffiti before (B) and after (A) will be:
d = A - B.

If the graffiti declined, it means that A will be smaller than B, therefore d should be negative.

Therefore we can set:
H₀ : μd  ≥ 0
H₁ : μd < 0 

The equal sign would mean that the number of graffiti incidents remained constant, therefore it is part of the null hypothesis.

Therefore the correct answer is B) H₀: μd ≥ 0 versus <span>H₁</span>: μd < 0

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Given <br><img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%28x%29%20%20%3D%20%20%5Cfrac%7B3%7D%7B%20log_%7Bxy%7D%282%29%20%7D%20
Naily [24]

Answer:

\displaystyle y = x^{-\frac{2}{3}}

Step-by-step explanation:

<u>Logarithms</u>

Some properties of logarithms will be useful to solve this problem:

1. \log(pq)=\log p+\log q

2. \displaystyle \log_pq=\frac{1}{\log_qp}

3. \displaystyle \log p^q=q\log p

We are given the equation:

\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }

Applying the second property:

\displaystyle  \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}

Substituting:

\displaystyle \log_{2}(x) = 3\log_{2}(xy)

Applying the first property:

\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))

Operating:

\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)

Rearranging:

\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)

Simplifying:

\displaystyle -2\log_{2}(x) =3\log_{2}(y)

Dividing by 3:

\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}

Applying the third property:

\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)

Applying inverse logs:

\boxed{y = x^{-\frac{2}{3}}}

7 0
3 years ago
4
Vinil7 [7]

Answer:

A: Measure of center, also known as the Median.

3 0
3 years ago
Barry's final score is 45 which player had the greater final score?
natali 33 [55]

The player with the greater final score is of:

Barry.

<h3>How to obtain which player had the greater final score?</h3>

Barry's final score is given as follows:

45.

Then we have to obtain Lee's score, from the description given in the missing information section.

Lee's scored is obtained as follows:

  • Starts at -350.
  • Answers a 275-point question correctly, hence - 350 + 275 = -75.
  • Answers a 70 - point question correctly, hence -75 + 70 = -5.
  • Answers a 50 - point question incorrectly, hence: -5 - 50 = -55.

Thus Lee's final score is given as follows:

-55.

The classifications of the final scores according to the signals are given as follows:

  • Barry: positive score.
  • Lee: negative score.

A positive score will always be greater than a negative score, hence Barry had the greater final score.

<h3>Missing information</h3>

Lee and Barry play a trivia game in which questions are worth different numbers of points. If a question is answered correctly, a player earns points. If a question is answered incorrectly, the player loses points. Lee currently has -350 points.

a. Before the game ends, Lee answers a 275 -point question correctly, a 70 -point question correctly, and a 50 -polnt question incorrectly. Write and find the value of an expression to find Lee's final score.

b. Barry's final score is 45. Which player had the greater final score?

More can be learned about addition of measures at brainly.com/question/24342899

#SPJ1

5 0
1 year ago
Please help! 60 points!
podryga [215]

Answer:

B

Step-by-step explanation:

try method B, hope it helps

4 0
3 years ago
Read 2 more answers
If an item that originally cost $13 is increased to $19, what is the percentage of increase in the item?
Evgesh-ka [11]
Original cost (OC) = $13

New cost (NC) = $19

Percentage increase = \frac{NC - OC}{OC} *100 =  \frac{19 - 13}{13} * 100 =  \frac{6}{13} * 100

= 46.15 %
4 0
3 years ago
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