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Sonja [21]
3 years ago
15

Identify the slope of the equation. Write your answer as an

Mathematics
1 answer:
baherus [9]3 years ago
6 0

Answer:

½

Step-by-step explanation:

we know y=mx+h

y= ½ x + 6 so m=½

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2/5 with an exponent of 3
ch4aika [34]

Answer:

2/5 with an exponent of 3 is 8/125 or 0.064

Step-by-step explanation:

Given:

A fraction = 2/5

Exponent = 3

To find the value of the fraction using the exponent.

We know that :

⇒ (a)^3=a\times a\times a  

The exponents is the number of times a number is multiplied.

So,

⇒ (\frac{2}{5})^3

⇒ \frac{2\times 2\times 2}{5\times 5\times 5}

⇒ \frac{8}{125}

On further division the number can be written as 0.064

5 0
3 years ago
What is the value of the 9 in 0.389​
Oksi-84 [34.3K]

Answer: nine thousandths

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
90 POINTSSSSSSSSSSS
sergey [27]
Y=3ˣ and y=2x+1
one of them is the grouth of the flies and the other is how many the iguana can eat per week (I'm thinking the y=3ˣ is the population growth)
where x=number of weeks and y=number of flies

so he should graph y=3ˣ and y=2x+1 and see the solution wich will be the inersection point of the 2 equations

to graph y=3ˣ, graph the points (0,0) and (1,3) and (2,9) and (5,243) then connect the points in a curve

to graph y=2x+1, graph the points (0,1) and (2,4) then connect the points with a straight line

where they intersect is the week and number of flies
to graph y=2x+1
6 0
3 years ago
Read 2 more answers
For your birthday, your parents take you to dinner and offer to let you have any 2 desserts on the menu. The restaurant, famous
dolphi86 [110]
I think there is 90 different combinations ? 
7 0
4 years ago
Read 2 more answers
Determine the region of the xy-plane where the solution of the DE would have a unique solution passing through the point (x0,y0)
Virty [35]

Answer:

given equation,

(9-y^2)\dfrac{dy}{dx}= x^4\\(9-y^2)dy = x^4 dx\\\int (9-y^2)dy =\int x^4 dx\\9y -\dfrac{y^3}{3} = \dfrac{x^5}{5}+C

so,

the given point from where the region is passing through is (x₀, y₀)

hence, the unique equation comes out to be

9y_0 -\dfrac{y_0^3}{3} = \dfrac{x_0^5}{5}+C

C = 9y_0 -\dfrac{y_0^3}{3}-\dfrac{x_0^5}{5}

hence unique equation,

9y -\dfrac{y^3}{3} = \dfrac{x^5}{5}+ 9y_0 -\dfrac{y_0^3}{3}-\dfrac{x_0^5}{5}

6 0
3 years ago
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