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3 years ago

Mhanifa or Anyone Answer this PLZZZZZZ

Mathematics

1 answer:

Len [333]3 years ago

3 0

Answer:

1 ABCD = 3 PQRS

Step-by-step explanation:

Given:

ABCD = PQRS

AD = PS

DC = SR

AD = PS

6 : 18

1 : 3

DC = SR

9 : 27

1 : 3

So,

1 ABCD = 3 PQRS

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3(x – 2) + 4x = 10(x + 1) will give brainliest

AlekseyPX

Answer:

x = -16/3

Step-by-step explanation:

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3 years ago

You take your friend out to dinner for their birthday. The bill was $65.00. You left $75.00 which includes the tip. What was the

kenny6666 [7]

Answer:

6.5%

Step-by-step explanation:

All i did was subtract 65 from the 75 which gave me 10 and I divided that by the original cost which was 65. That gave me 6.5%. Another possible answer is 0.1538461538461538. I just tried my best.

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3 years ago

Twenty-five samples of 100 items each were inspected when a process was considered to be operating satisfactorily. In the 25 sam

notsponge [240]

a) The estimate of the proportion of defectives when the process is in control is 0.054

b) The standard error of the proportion if the sample size is 100 is 0.0226.

c) The upper control limit is 0.1218 and the lower control limit is 0 (since LCL < 0 and p > 0, we can write LCL = 0).

<h3>What are the formulas for finding the estimate of the proportion, standard variation, and control limits?</h3>

1) The estimate of the proportion of success is

p = (number of success)/(total number of samples)

I.e., p = x/N

2) The standard deviation of the proportion of success is

$\sigma_p = \sqrt{\frac{p(1-p)}{n} }$

3) The upper and lower control limits for a control chart are:

L.C.L = p - 3 $\sigma_p$

and U.C.L = p + 3 $\sigma_p$

<h3>Calculation:</h3>

It is given that, there are 25 samples of 100 items each.

So, the total number of items i.e., the total sample size,

N = 25 × 100 = 2500

In 25 samples, a total of 135 items were found to be defective.

So, the number of defectives x = 135

a) The estimate of the proportion of defectives is p = x/N

On substituting, we get

p = 135/2500 = 0.054

b) The standard error of the proportion if the sample of size 100 is calculated by

$\sigma_p = \sqrt{\frac{p(1-p)}{n} }$

On substituting p = 0.054 and n = 100, we get

$\sigma_p = \sqrt{\frac{0.054(1-0.54)}{100} }$

= 0.0226

c) The control limits for the control chart are:

Upper control limit = p + 3 $\sigma_p$

⇒ U.C.L = 0.054 + 3(0.0226) = 0.054 + 0.0678 = 0.1218

Lower control limit = p - 3 $\sigma_p$

⇒ L.C.L = 0.054 - 3(0.0226) = 0.054 - 0.0678 = - 0.0138 ≈ 0

(Since we know that the lower control limit should not be a negative value, it is made equal to 0).

Learn more about an estimate of the proportion here:

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7 0

1 year ago

Someone please help me?!?!

statuscvo [17]

Holy guacamole....oml

7 0

3 years ago

EXAMPLE 3 Show that the curvature of a circle of radius k is 1/k. SOLUTION We can take the circle to have center the origin, and

Anastasy [175]

Answer:

Therefore r'(t) =-k sin t i + k cos t j and |r'(t)| = k so T(t) = r'(t)/|r'(t)| = -sin t i + cos t j and T'(t) = -cos t i- sin t j . This gives |T'(t)| = 1, so using this equation, we have κ(t) = |T'(t)|/|r'(t)| = 1/k.

Step-by-step explanation:

We are already given the definition of curvature and the parametrization needed to find the curvature of the circle. In genecral the curvature κ is equal to κ(t)=|T'(t)|/|r'(t)| where r(t) is a parametrization of the curve and T(t) is the normalized tangent vector respect to the parametrization, that is, T(t)=r'(t)/|r'(t)|.

Now, using the derivatives of sines and cosines, and the definition of norm, we obtain that:

r(t) = k cos t i + k sin t j ⇒ r'(t)=-k sin t i + k cos t j ⇒|r'(t)|²=sin²t+cos²t=1

T(t) = r'(t)/|r'(t)|=-sin t i +cos t j ⇒ T'(t)= -cos t i - sin t j ⇒|T'(t)|²=cos²t+sin²t=1

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4 years ago