Answer:
a) 20<h≤30.
b) 26.17 hrs
Step-by-step explanation:
The missing table is shown in attachment.
Part a)
We need to find the class interval that contains the median.
The total frequency is
The median class corresponds to half
That is the 15th value.
We start adding the frequency from the top obtain the least cumulative frequency greater or equal to 15.
2+8+9=19
This corresponds to the class interval 20<h≤30.
Adding from the bottom also gives the same result.
Therefore the median class is 20<h≤30.
b) Since this is a grouped data we use the midpoint to represent the class.
The median is given by :
Answer:
x - 2y = 2
Step-by-step explanation:
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and A, B are integers )
given y = 
x - 1
multiply through by 2 to eliminate the fraction
2y = x - 2 ( subtract 2y from both sides )
0 = x - 2y - 2 ( add 2 to both sides )
x - 2y = 2 ← in standard form
Answer:
6+ 45 = 500 #!_ djdjbdkeknf
well 3x15= 45 and 15x17= 255 so 45+255= 300
Remember, parenthaees are like < and > and brackets ar like ≤ and ≥
domain is how far the x values go
x is left to right
we see they go from -3 to 5, with a filled in dot at -3 and empty dot at 5
means include -3 but not including 5
so like -3≤x<5
or in interval notation
[-3,5) is the domain
range
highest to lowest y value
range is from y=3 to y=-1
we gots full dots so we use brackets
range is [-1,3]
Domain=[-3,5)
Range=[-1,3]
B. read above and understand it
