Please put a more clear picture
Answer:
42°
Step-by-step explanation:
Altitude of an isosceles triangle divides it vertex in equal angles
so ∠ABD = ∠PBC = 48/2 = 24
In ΔABC sum of angles = 180 and ∠A = ∠C
48 + A + C = 180
2A = 180 - 48 = 132
A = 132/2 = 66 = ∠C
As PB = PC ---> ∠PBC = ∠PCB = 24
∠ACB = 66 = ∠PCD + ∠PCB
66 = ∠PCD + 24
∠PCD = 42
-15 7/40
Convert a mixed number by placing the numbers to the right of the decimal over
1000.
<em>n = - 1</em>
- <em>Step-by-step explanation:</em>
<em>Hi ! </em>
<em>6 = - 2(10n + 7)</em>
<em>6 = - 20n - 14</em>
<em>20n = - 6 - 14</em>
<em>20n = - 20</em>
<em>n = - 20 : 20</em>
<em>n = - 1</em>
<em />
<em>6 = - 2(10×-1 + 7)</em>
<em>6 = - 2(-10 + 7)</em>
<em>6 = - 2(-3)</em>
<em>6 = 6 (true)</em>
<em>Good luck !</em>
Answer:
A point is chosen at random inside the cylinder, then probability the point belongs outside of the spheres is 0.25
Step-by-step explanation:
Let's find volume of the cylinder and volume of the three spheres.
Volume of cylinder =
Volume of sphere =
Now, r =2.7
h=8.1
Find volume of each shape.
Volume of cylinder =
=59.049
Now, volume of 3 spheres =
=78.732
Now, p(E)=
So, Probability of point is chosen at random inside the cylinder which belongs outside of the spheres is

Let's simplify them
0.25
A point is chosen at random inside the cylinder, then probability the point belongs outside of the spheres is 0.25