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balu736 [363]
2 years ago
15

Graph the image of the given triangle under a dilation with a scale factor of 12 and the center of dilation ​ (0, 0) ​ .

Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
4 0

Answer:

brainly.com/question/10891847

Step-by-step explanation:

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The sides of two cubes are in the ratio 2:1. What is the ratio of their volumes ?
olasank [31]

Please mark as brainliest

Answer:

we know that, Volume of cube=a³

Let volume of 1st cube be 2x with side a and other be x with side A (according to given ratio)

Step-by-step explanation:

ATQ: 2x=a³ and, x=A³

a=³√2x and, A=x

we know that, surface area of cube is 6a²

Thus, surface area of 1st cube = 6(³√2x)²

= 6³√4x²

Surface area of 2nd cube=6(x)²=6x²

Ratio of S.A=(6³√4x²)÷(6x²)

Ratio of S.A=³√4:1

<em><u>Please mark as brainliest</u></em>

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5 0
2 years ago
Need help ASAP! I’m very confused!
Ahat [919]

Answer:

4 would be your answer

Step-by-step explanation:

brainlesit pls

8 0
2 years ago
It takes 10 pounds of potatoes to make 15 servings of mashed potatoes. At this rate:
UkoKoshka [18]

Answer:

1. 15 1/2

Step-by-step explanation:

6 0
2 years ago
The sum of two consecutive even integers is 74
olasank [31]
Edited in the comment ............
4 0
3 years ago
The line l is tangent to the circle with equation x^2 + y^2=10 at the point P.
babunello [35]

Given:

The equation of a circle is

x^2+y^2=10

A tangent line l to the circle touches the circle at point P(1,3).

To find:

The equation of the line l.

Solution:

Slope formula: If a line passes through two points, then the slope of the line is

m=\dfrac{y_2-y_1}{x_2-x_1}

Endpoints of the radius are O(0,0) and P(1,3). So, the slope of radius is

m_1=\dfrac{3-0}{1-0}

m_1=\dfrac{3}{1}

m=3

We know that the radius of a circle is always perpendicular to the tangent at the point of tangency.

Product of slopes of two perpendicular lines is always -1.

Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.

m\times m_1=-1

m\times 3=-1

m=-\dfrac{1}{3}

The slope of line l is -\dfrac{1}{3} and it passs through the point P(1,3). So, the equation of line l is

y-y_1=m(x-x_1)

y-3=-\dfrac{1}{3}(x-1)

y-3=-\dfrac{1}{3}(x)+\dfrac{1}{3}

Adding 3 on both sides, we get

y=-\dfrac{1}{3}x+\dfrac{1}{3}+3

y=-\dfrac{1}{3}x+\dfrac{1+9}{3}

y=-\dfrac{1}{3}x+\dfrac{10}{3}

Therefore, the equation of line l is y=-\dfrac{1}{3}x+\dfrac{10}{3}.

4 0
2 years ago
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