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kolezko [41]
2 years ago
7

The secret to football betting​

Mathematics
1 answer:
padilas [110]2 years ago
8 0
What is the SECRET to football BETTING ??
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Find the root(s) of f (x) = (x + 5)3(x - 9)2(x + 1). -5 with multiplicity 3 5 with multiplicity 3 -9
faust18 [17]

Answer:

  -5, multiplicity 3; +9, multiplicity 2; -1

Step-by-step explanation:

The roots of f(x) are those values of x that make the factors be zero. For a factor of x-a, the root is x=a, because a-a=0. If the factor appears n times, then the root has multiplicity n.

f(x) = (x+5)^3(x-9)^2(x+1) has roots ...

  • -5 with multiplicity 3
  • +9 with multiplicity 2
  • -1
4 0
2 years ago
A negative correlation between two variables x and y usually yields a negative p-value for r.
Harman [31]
A. True if im wrong sorry hope this helped tho :p
6 0
3 years ago
Factor the quadratic expression completely<br> 6x^2 – 28x + 32
Fiesta28 [93]
Answer: 2(x-2)(3x-8)

7 0
3 years ago
Anyone know how to solve this??
Tom [10]

Given : \frac{(x^\frac{2}{5})^9\;.\;(x^\frac{-4}{15})}{x^\frac{1}{3}}

\implies {(x^\frac{18}{5})\;.\; (x^\frac{-4}{15})}\;.\;(x^\frac{-1}{3})

\implies x^(^\frac{18}{5} ^-^\frac{4}{15}^-^\frac{1}{3}^)

\implies x^(^(^\frac{54 - 4}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{50}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{10}{3}^)^-^\frac{1}{3}^) = x^(^\frac{9}{3}^) = x^3

\implies x^k = x^3

\implies k = 3

7 0
3 years ago
Find the value of (-3/8) x (+8/15
Mekhanik [1.2K]

\frac{ - 3}{8}  \times  \frac{8}{15}  \\  \\  = \frac{  \cancel{- 3}}{ \cancel8}  \times  \frac{ \cancel8}{ \cancel{15}} \\  \\  =  -  \frac{1}{5}

Hope This Helps ~

8 0
1 year ago
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