For each situation(the boat going upstream, the boat going downstream) make an equation to show how to calculate the distance, D
, that the boat can cover during time, T.
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Look at the photo
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If the speed of the boat if 4 mph and the time is T, the equation of the distance is D= ___
If the speed of the boat I’d 9 mph and the time is T, the equation of the distance is D= ___
(Find the blanks)
—-
Look at the photo
—-
If the speed of the boat if 4 mph and the time is T, the equation of the distance is D= ___
If the speed of the boat I’d 9 mph and the time is T, the equation of the distance is D= ___
(Find the blanks)
1 answer:
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The 400th term is 425.
There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are![\lfloor\sqrt[6]{427}\rfloor=2](https://tex.z-dn.net/?f=%5Clfloor%5Csqrt%5B6%5D%7B427%7D%5Crfloor%3D2)
numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 = 425.
There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are